CODEWITHSUNDEEP
c++stllanguage-lawyerstdstringtemporary-objects
user1095108
user1095108

Reputation: 14603

Is it safe to use the std::string::c_str() of a temporary string?

Is the following C++ code well-formed?

void consumer(char const* p)
{
  std::printf("%s", p);
}

std::string random_string_generator();

consumer(random_string_generator().c_str());

The problem I have with it is, that after creating the temporary std::string object and taking the c_str() pointer, nothing prevents the std::string object from getting destroyed, unless I'm wrong.

Is this code well-formed according to the standard? It does work, when I test with g++.

Upvotes: 79

Views: 14056

Answers (3)

James Kanze
James Kanze

Reputation: 153939

The pointer returned by std::string::c_str() points to memory maintained by the string object. It remains valid until a non-const function is called on the string object, or the string object is destructed. The string object you're concerned about is a temporary. It will be destructed at the end of the full expression, not before and not after. In your case, the end of the full expression is after the call to consumer, so your code is safe. It wouldn't be if consumer saved the pointer somewhere, with the idea of using it later.

The lifetime of temporaries has been strictly defined since C++98. Before that, it varied, depending on the compiler, and the code you've written wouldn't have worked with g++ (pre 1995, roughly—g++ changed this almost immediately when the standards committee voted it). (There wasn't an std::string then either, but the same issues affect any user written string class.)

Upvotes: 99

dgulabs
dgulabs

Reputation: 473

The temporary returned by the function random_string_generator() can be used in consumer() function safely.

Upvotes: 6

Jon
Jon

Reputation: 437454

The temporary std::string's lifetime extends just beyond the point where consumer returns, so it is safe to use anything on that string directly from within consumer. What is not OK is to store the value that c_str returns and try to use it later (the temporary will have been destroyed, and we can only guess what you will find at the other end of the pointer).

Upvotes: 27

Related Questions