Reputation: 4369

Removing a list of characters in string

I want to remove characters in a string in python:

string.replace(',', '').replace("!", '').replace(":", '').replace(";", '')...

But I have many characters I have to remove. I thought about a list

list = [',', '!', '.', ';'...]

But how can I use the list to replace the characters in the string?

Upvotes: 241

Answers (20)

Shaida Muhammad

Reputation: 1650

Why not utilize this simple function:

def remove_characters(str, chars_list):
    for char in chars_list:
        str = str.replace(char, '')
  
    return str

Use function:

print(remove_characters('A.B!C?', ['.', '!', '?']))

Output:

ABC

Upvotes: 1

Linlin林林

Reputation: 31

In Python 3.8, this works for me:

s.translate(s.maketrans(dict.fromkeys(',!.;', '')))

Upvotes: 3

krystan honour

Reputation: 6783

you could use something like this

def replace_all(text, dic):
  for i, j in dic.iteritems():
    text = text.replace(i, j)
  return text

This code is not my own and comes from here its a great article and dicusses in depth doing this

Upvotes: 6

Biplob Das

Reputation: 3094

Remove *%,&@! from below string:

s = "this is my string,  and i will * remove * these ** %% "
new_string = s.translate(s.maketrans('','','*%,&@!'))
print(new_string)

# output: this is my string  and i will  remove  these

Upvotes: 5

John Forbes

Reputation: 1354

Python 3, single line list comprehension implementation.

from string import ascii_lowercase # 'abcdefghijklmnopqrstuvwxyz'
def remove_chars(input_string, removable):
  return ''.join([_ for _ in input_string if _ not in removable])

print(remove_chars(input_string="Stack Overflow", removable=ascii_lowercase))
>>> 'S O'

Upvotes: 1

pylang

Reputation: 44465

Here is a more_itertools approach:

import more_itertools as mit


s = "A.B!C?D_E@F#"
blacklist = ".!?_@#"

"".join(mit.flatten(mit.split_at(s, pred=lambda x: x in set(blacklist))))
# 'ABCDEF'

Here we split upon items found in the blacklist, flatten the results and join the string.

Upvotes: 1

perfecto25

Reputation: 842

simple way,

import re
str = 'this is string !    >><< (foo---> bar) @-tuna-#   sandwich-%-is-$-* good'

// condense multiple empty spaces into 1
str = ' '.join(str.split()

// replace empty space with dash
str = str.replace(" ","-")

// take out any char that matches regex
str = re.sub('[!@#$%^&*()_+<>]', '', str)

output:

this-is-string--foo----bar--tuna---sandwich--is---good

Upvotes: 5

Hiskel Kelemework

Reputation: 44

i think this is simple enough and will do!

list = [",",",","!",";",":"] #the list goes on.....

theString = "dlkaj;lkdjf'adklfaj;lsd'fa'dfj;alkdjf" #is an example string;
newString="" #the unwanted character free string
for i in range(len(TheString)):
    if theString[i] in list:
        newString += "" #concatenate an empty string.
    else:
        newString += theString[i]

this is one way to do it. But if you are tired of keeping a list of characters that you want to remove, you can actually do it by using the order number of the strings you iterate through. the order number is the ascii value of that character. the ascii number for 0 as a char is 48 and the ascii number for lower case z is 122 so:

theString = "lkdsjf;alkd8a'asdjf;lkaheoialkdjf;ad"
newString = ""
for i in range(len(theString)):
     if ord(theString[i]) < 48 or ord(theString[i]) > 122: #ord() => ascii num.
         newString += ""
     else:
        newString += theString[i]

Upvotes: 2

Dekel

Reputation: 62536

If you are using python3 and looking for the translate solution - the function was changed and now takes 1 parameter instead of 2.

That parameter is a table (can be dictionary) where each key is the Unicode ordinal (int) of the character to find and the value is the replacement (can be either a Unicode ordinal or a string to map the key to).

Here is a usage example:

>>> list = [',', '!', '.', ';']
>>> s = "This is, my! str,ing."
>>> s.translate({ord(x): '' for x in list})
'This is my string'

Upvotes: 45

Akshay Hazari

Reputation: 3267

How about this - a one liner.

reduce(lambda x,y : x.replace(y,"") ,[',', '!', '.', ';'],";Test , ,  !Stri!ng ..")

Upvotes: 2

georg

Reputation: 214949

If you're using python2 and your inputs are strings (not unicodes), the absolutely best method is str.translate:

>>> chars_to_remove = ['.', '!', '?']
>>> subj = 'A.B!C?'
>>> subj.translate(None, ''.join(chars_to_remove))
'ABC'

Otherwise, there are following options to consider:

A. Iterate the subject char by char, omit unwanted characters and join the resulting list:

>>> sc = set(chars_to_remove)
>>> ''.join([c for c in subj if c not in sc])
'ABC'

(Note that the generator version ''.join(c for c ...) will be less efficient).

B. Create a regular expression on the fly and re.sub with an empty string:

>>> import re
>>> rx = '[' + re.escape(''.join(chars_to_remove)) + ']'
>>> re.sub(rx, '', subj)
'ABC'

(re.escape ensures that characters like ^ or ] won't break the regular expression).

C. Use the mapping variant of translate:

>>> chars_to_remove = [u'δ', u'Γ', u'ж']
>>> subj = u'AжBδCΓ'
>>> dd = {ord(c):None for c in chars_to_remove}
>>> subj.translate(dd)
u'ABC'

Full testing code and timings:

#coding=utf8

import re

def remove_chars_iter(subj, chars):
    sc = set(chars)
    return ''.join([c for c in subj if c not in sc])

def remove_chars_re(subj, chars):
    return re.sub('[' + re.escape(''.join(chars)) + ']', '', subj)

def remove_chars_re_unicode(subj, chars):
    return re.sub(u'(?u)[' + re.escape(''.join(chars)) + ']', '', subj)

def remove_chars_translate_bytes(subj, chars):
    return subj.translate(None, ''.join(chars))

def remove_chars_translate_unicode(subj, chars):
    d = {ord(c):None for c in chars}
    return subj.translate(d)

import timeit, sys

def profile(f):
    assert f(subj, chars_to_remove) == test
    t = timeit.timeit(lambda: f(subj, chars_to_remove), number=1000)
    print ('{0:.3f} {1}'.format(t, f.__name__))

print (sys.version)
PYTHON2 = sys.version_info[0] == 2

print ('\n"plain" string:\n')

chars_to_remove = ['.', '!', '?']
subj = 'A.B!C?' * 1000
test = 'ABC' * 1000

profile(remove_chars_iter)
profile(remove_chars_re)

if PYTHON2:
    profile(remove_chars_translate_bytes)
else:
    profile(remove_chars_translate_unicode)

print ('\nunicode string:\n')

if PYTHON2:
    chars_to_remove = [u'δ', u'Γ', u'ж']
    subj = u'AжBδCΓ'
else:
    chars_to_remove = ['δ', 'Γ', 'ж']
    subj = 'AжBδCΓ'

subj = subj * 1000
test = 'ABC' * 1000

profile(remove_chars_iter)

if PYTHON2:
    profile(remove_chars_re_unicode)
else:
    profile(remove_chars_re)

profile(remove_chars_translate_unicode)

Results:

2.7.5 (default, Mar  9 2014, 22:15:05) 
[GCC 4.2.1 Compatible Apple LLVM 5.0 (clang-500.0.68)]

"plain" string:

0.637 remove_chars_iter
0.649 remove_chars_re
0.010 remove_chars_translate_bytes

unicode string:

0.866 remove_chars_iter
0.680 remove_chars_re_unicode
1.373 remove_chars_translate_unicode

---

3.4.2 (v3.4.2:ab2c023a9432, Oct  5 2014, 20:42:22) 
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)]

"plain" string:

0.512 remove_chars_iter
0.574 remove_chars_re
0.765 remove_chars_translate_unicode

unicode string:

0.817 remove_chars_iter
0.686 remove_chars_re
0.876 remove_chars_translate_unicode

(As a side note, the figure for remove_chars_translate_bytes might give us a clue why the industry was reluctant to adopt Unicode for such a long time).

Upvotes: 284

Sheikh Ahmad Shah

Reputation: 281

I am thinking about a solution for this. First I would make the string input as a list. Then I would replace the items of list. Then through using join command, I will return list as a string. The code can be like this:

def the_replacer(text):
    test = []    
    for m in range(len(text)):
        test.append(text[m])
        if test[m]==','\
        or test[m]=='!'\
        or test[m]=='.'\
        or test[m]=='\''\
        or test[m]==';':
    #....
            test[n]=''
    return ''.join(test)

This would remove anything from the string. What do you think about that?

Upvotes: 1

rioted

Reputation: 1092

Perhaps a more modern and functional way to achieve what you wish:

>>> subj = 'A.B!C?'
>>> list = set([',', '!', '.', ';', '?'])
>>> filter(lambda x: x not in list, subj)
'ABC'

please note that for this particular purpose it's quite an overkill, but once you need more complex conditions, filter comes handy

Upvotes: 4

Sylvain

Reputation: 413

Also an interesting topic on removal UTF-8 accent form a string converting char to their standard non-accentuated char:

What is the best way to remove accents in a python unicode string?

code extract from the topic:

import unicodedata

def remove_accents(input_str):
    nkfd_form = unicodedata.normalize('NFKD', input_str)
    return u"".join([c for c in nkfd_form if not unicodedata.combining(c)])

Upvotes: 4

Sven Marnach

Reputation: 601471

You can use str.translate():

s.translate(None, ",!.;")

Example:

>>> s = "asjo,fdjk;djaso,oio!kod.kjods;dkps"
>>> s.translate(None, ",!.;")
'asjofdjkdjasooiokodkjodsdkps'

Upvotes: 120

tcpiper

Reputation: 2544

These days I am diving into scheme, and now I think am good at recursing and eval. HAHAHA. Just share some new ways:

first ,eval it

print eval('string%s' % (''.join(['.replace("%s","")'%i for i in replace_list])))

second , recurse it

def repn(string,replace_list):
    if replace_list==[]:
        return string
    else:
        return repn(string.replace(replace_list.pop(),""),replace_list)

print repn(string,replace_list)

Hey ,don't downvote. I am just want to share some new idea.

Upvotes: 1

aIKid

Reputation: 28242

Why not a simple loop?

for i in replace_list:
    string = string.replace(i, '')

Also, avoid naming lists 'list'. It overrides the built-in function list.

Upvotes: 11

alan

Reputation: 4842

Another approach using regex:

''.join(re.split(r'[.;!?,]', s))

Upvotes: 9

ninjagecko

Reputation: 91094

''.join(c for c in myString if not c in badTokens)

Upvotes: 18

Praveen Gollakota

Reputation: 38930

You can use the translate method.

s.translate(None, '!.;,')

Upvotes: 37

Removing a list of characters in string

Answers (20)

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