CODEWITHSUNDEEP
javascript
johnwp
johnwp

Reputation: 766

Using function results in "function source code" and not evaluated function value?

The following code sample (also at http://jsfiddle.net/MZwBS/)

var items = [];

items.push({
    example: function() {
        if(0 > 1) {
            return 'true';
        } else {
            return 'false';
        }
    }
});

document.write(items[0].example);

produces

'function () { if (0 > 1) { return "true"; } else { return "false"; } }'

instead of

'false'

It seems like I've been able something like this with ExtJS. Can anyone tell me where I went wrong? I'd like to evaluate anonymous functions like this on-the-fly.

Upvotes: 3

Views: 121

Answers (3)

johnwp
johnwp

Reputation: 766

I've solved my issue by adding '()' after the anonymous function as shown below.
http://jsfiddle.net/MZwBS/7/

var items = [];

items.push({
    example: function() {
        if(0 > 1) {
            return 'true';
        } else {
            return 'false';
        }
    }()
});

document.write(items[0].example);

This code block now produces the expected result of

'false'

Upvotes: 0

meder omuraliev
meder omuraliev

Reputation: 186672

Do you mean to execute it?

document.write(items[0].example());​

Upvotes: 3

Kendall Frey
Kendall Frey

Reputation: 44374

You want:

document.write(items[0].example());

When you skip the parentheses, you are saying, "Print this function." When you have them, you are saying, "Evaluate this function and print the result."

Upvotes: 2

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