Reputation: 541
I want a regex in JavaScript for validating decimal numbers.
It should allow only up to two decimal places. For example, it should allow 10.89
but not 10.899
.
It should also allow only one period (.
). For example, it should allow 10.89
but not 10.8.9
.
Upvotes: 39
Views: 172981
Reputation: 47081
/^\d+(\.\d{1,2})?$/
/^-?\d+(\.\d{1,2})?$/
var regexp = /^\d+(\.\d{1,2})?$/;
console.log("POSITIVE ONLY");
console.log("'.74' returns " + regexp.test('.74'));
console.log("'7' returns " + regexp.test('7'));
console.log("'-4' returns " + regexp.test('-4'));
console.log("'10.5' returns " + regexp.test('10.5'));
console.log("'115.25' returns " + regexp.test('115.25'));
console.log("'-120.56' returns " + regexp.test('-120.56'));
console.log("'1535.803' returns " + regexp.test('1535.803'));
console.log("'153.14.5' returns " + regexp.test('153.14.5'));
console.log("'415351108140' returns " + regexp.test('415351108140'));
console.log("'415351108140.55' returns " + regexp.test('415351108140.55'));
console.log("'415351108140.556' returns " + regexp.test('415351108140.556'));
regexp = /^-?\d+(\.\d{1,2})?$/;
console.log("\n");
console.log("POSITIVE OR NEGATIVE");
console.log("'.74' returns " + regexp.test('.74'));
console.log("'7' returns " + regexp.test('7'));
console.log("'-4' returns " + regexp.test('-4'));
console.log("'10.5' returns " + regexp.test('10.5'));
console.log("'115.25' returns " + regexp.test('115.25'));
console.log("'-120.56' returns " + regexp.test('-120.56'));
console.log("...");
/ /
: the beginning and end of the expression^
: whatever follows should be at the beginning of the string you're testing\d+
: there should be at least one digit( )?
: this part is optional\.
: here goes a dot\d{1,2}
: there should be between one and two digits here$
: whatever precedes this should be at the end of the string you're testingIf you also want to support negative decimals, you just need to add -?
right after the ^
, which means that an optional minus sign is allowed there as well.
You can use regexr.com or regex101.com for testing regular expressions directly in the browser!
Upvotes: 54
Reputation: 127
Since you asked for decimal numbers validation, for completeness' sake, I'd use a regex that doesn't allow strings like 06.05.
^((0(\.\d{1,2})?)|([1-9]\d*(\.\d{1,2})?))$
Slightly more complicated, but returns false in that case.
Edit:
^-?((0(\.\d{1,2})?)|([1-9]\d*(\.\d{1,2})?))$
if you want negative numbers as well.
Upvotes: 3
Reputation: 21
The schema for passing the value in as a string. The regex will validate a string of at least one digit, possibly followed by a period and exactly two digits:
{
"type": "string",
"pattern": "^[0-9]+(\\.[0-9]{2})?$"
}
The schema below is equivalent, except that it also allows empty strings:
{
"type": "string",
"pattern": "^$|^[0-9]+(\\.[0-9]{2})?$"
}
Upvotes: 0
Reputation: 1761
function CheckValidAmount() {
var amounttext = document.getElementById('txtRemittanceNumber').value;
if (!(/^[-+]?\d*\.?\d*$/.test(amounttext))){
alert('Please enter only numbers into amount textbox.')
document.getElementById('txtRemittanceNumber').value = "10.00";
}
}
This is the function which will take decimal number with any number of decimal places and without any decimal places.
Thanks ... :)
Upvotes: 0
Reputation: 707
Please see my project of the cross-browser filter of value of the text input element on your web page using JavaScript language: Input Key Filter . You can filter the value as an integer number, a float number, or write a custom filter, such as a phone number filter. See an example of custom filter of input of an float number with decimal pointer and limitation to 2 digit after decimal pointer:
<!doctype html>
<html xmlns="http://www.w3.org/1999/xhtml" >
<head>
<title>Input Key Filter Test</title>
<meta name="author" content="Andrej Hristoliubov [email protected]">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<!-- For compatibility of IE browser with audio element in the beep() function.
https://www.modern.ie/en-us/performance/how-to-use-x-ua-compatible -->
<meta http-equiv="X-UA-Compatible" content="IE=9"/>
<link rel="stylesheet" href="https://rawgit.com/anhr/InputKeyFilter/master/InputKeyFilter.css" type="text/css">
<script type="text/javascript" src="https://rawgit.com/anhr/InputKeyFilter/master/Common.js"></script>
<script type="text/javascript" src="https://rawgit.com/anhr/InputKeyFilter/master/InputKeyFilter.js"></script>
</head>
<body>
<h1>Float field</h1>
<input id="Float"
onchange="javascript: onChangeFloat(this)"
onblur="inputKeyFilter.isNaN(parseFloat(this.value), this);"
/>
<script>
function CreateFloatFilterCustom(elementID, onChange, onblur){
try{
inputKeyFilter.Create(elementID
, onChange
, function(elementInput, value){//customFilter
if(value.match(/^(-?\d*)((\.(\d{0,2})?)?)$/i) == null){
inputKeyFilter.TextAdd(isRussian() ?
"Допустимый формат: -[0...9].[0...9] или -[0...9]e-[0...9]. Например: -12.34 1234"
: "Acceptable formats: -[0...9].[0...9] or -[0...9]e-[0...9]. Examples: -12.34 1234"
, elementInput);
return false;
}
return true;
}
, onblur
)
} catch(e) {
consoleError("Create float filter failed. " + e);
}
}
CreateFloatFilterCustom("Float");
function onChangeFloat(input){
inputKeyFilter.RemoveMyTooltip();
var elementNewFloat = document.getElementById("NewFloat");
var float = parseFloat(input.value);
if(inputKeyFilter.isNaN(float, input)){
elementNewFloat.innerHTML = "";
return;
}
elementNewFloat.innerHTML = float;
}
</script>
New float: <span id="NewFloat"></span>
</body>
</html>
Also see my page example of the input key filter
Upvotes: 4
Reputation: 31
Try a regular expression like this:
(?=[^\0])(?=^([0-9]+){0,1}(\.[0-9]{1,2}){0,1}$)
Allowed: 1, 10.8, 10.89, .89, 0.89, 1000
Not Allowed: 20. , 50.89.9, 12.999, ., Null character Note this works for positive numbers
Upvotes: 3
Reputation: 1003
I found that I could use
^\d+(\.\d+)?$
for more than two decimal places.
Upvotes: 4
Reputation: 685
Numbers with at most 2 decimal places:
/^\d+(?:\.\d{1,2})?$/
This should work fine. Please try out :)
Upvotes: 4
Reputation: 271
as compared from the answer gven by mic... it doesnt validate anything in some of the platforms which i work upon... to be precise it doesnt actually work out in Dream Viewer..
hereby.. i re-write it again..which will work on any platform.. "^[0-9]+(.[0-9]{1,2})?$".. thnkss..
Upvotes: 0
Reputation: 4821
Try the following expression: ^\d+\.\d{0,2}$
If you want the decimal places to be optional, you can use the following: ^\d+(\.\d{1,2})?$
EDIT: To test a string match in Javascript use the following snippet:
var regexp = /^\d+\.\d{0,2}$/;
// returns true
regexp.test('10.5')
Upvotes: 54
Reputation: 9202
^\d+(\.\d{1,2})?$
will allow:
244
10.89
9.5
will disallow:
10.895
10.
10.8.9
Upvotes: 43