CODEWITHSUNDEEP
phpdatetimedatetimezone
Giordano Giuliano
Giordano Giuliano

Reputation: 757

Error when trying to create an object DateTime in PHP

Today I got a project written in PHP. There's an error when I try to show a date in a table data set. This is the statement that generates the error:

$data = new DateTime($registro["previsao de entrega"];

The error message is this:

Fatal error: Uncaught exception 'Exception' with message 'DateTime::__construct() Failed to parse time string (2 dez 2011 16:00) at position 0 (2): Unexpected character' in C:\www\fluxo_producao\Telas\TelaFluxoProducao.php:941 Stack trace: #0 C:\www\fluxo_producao\Telas\TelaFluxoProducao.php(941): DateTime->__construct('2 dez 2011 16:0...') #1 {main} thrown in C:\www\fluxo_producao\Telas\TelaFluxoProducao.php on line 941

What I discovered by myself was that if I change the parameter manually to "12 Dec 2006" for example, the function works. But the date the variable is passing is "12 Dez 2006" (Brazilian format, by the way, I'm Brazilian ^_^), and i found too that the default timezone in the server is "America/Sao_Paulo"... What do I have to change in the function or parameters to make it convert the format specified?

Upvotes: 1

Views: 1745

Answers (2)

DaveRandom
DaveRandom

Reputation: 88647

Verify that you have set your server to the correct time locale:

setlocale(LC_TIME, 'pt_BR');

This is required for strftime() and AFAIK all the date/time related functions and the DateTime class use the same library which will require/respect this setting.

Upvotes: 0

472084
472084

Reputation: 17886

It needs to have a closing curly bracket on the end?

$data = new DateTime($registro["previsao de entrega"]);

If this is just a typo it could be the value of $registro["previsao de entrega"] is incorrect, what is it?

You can see allowed value formats here: http://www.php.net/manual/en/datetime.formats.date.php

It will only accept English month values, eg, Dec will work but Dez will not.

Upvotes: 1

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