Reputation: 5880
I have a Python script that manages a series of CasperJS tasks and processes the result. It runs well from the command line, but when I run the script in cron, I get the error:
CalledProcessError: Command '['/path/to/casperjs', '/path/to/doSomething.js', 'args']' returned non-zero exit status 1
In Python, I call CasperJS:
response = subprocess.check_output(['/path/to/casperjs', '/path/to/doSomething.js', 'args'], shell=True)
I have tried shell=False
and Popen
as well, but I get the same result. I also tried making the entire command a string (instead of list), but that didn't help either.
Running '/path/to/casperjs /path/to/doSomething.js args'
returns exit code 0 when run in the shell.
I have also added PATH=/usr/bin:/bin:/sbin:/usr/local/bin
to my crontab to no avail. (As suggested in this question.)
Any ideas why I'm only getting this error in cron? Thanks!!
EDIT: In accordance with the answer below, setting shell=False
and stderr=subprocess.STDOUT
made everything work...
Upvotes: 7
Views: 28716
Reputation: 1
This is because when shell=True
is chosen, the first arg is interpreted differently than when shell=False
. In the second case, string or array is allowed, but it appears when shell is used the string form is preferred.
The docs are vague about this: "If passing a single string, either shell must be True (see below) or else the string must simply name the program to be executed without specifying any arguments."
You can remedy this EITHER by setting shell=False
or by setting it to true and passing in the command as a string.
Upvotes: 0
Reputation: 92637
You should try to capture stderr in addition to stdout so that you can find out exactly why the program is failing (assuming it does indeed print some errors for you)
cmd = ['/path/to/casperjs', '/path/to/doSomething.js', 'args']
response = subprocess.check_output(cmd,
shell=True,
stderr=subprocess.STDOUT)
Upvotes: 11