Reputation: 258
I have a test next week for c++ and I'm preparing myself for it. I'm confused when I have 2 classes as shown below. I have to walk through the execution of the code, line by line, and I'm confused about the marked lines (x = ...
and y = ...
inside class two
) - where does execution go from there?
#include <iostream>
using namespace std;
class one {
int n;
int m;
public:
one() { n = 5; m = 6; cout << "one one made\n"; }
one(int a, int b) {
n = a;
m = b;
cout << "made one one\n";
}
friend ostream &operator<<(ostream &, one);
};
ostream &operator<<(ostream &os, one a) {
return os << a.n << '/' << a.m << '=' <<
(a.n/a.m) << '\n';
}
class two {
one x;
one y;
public:
two() { cout << "one two made\n"; }
two(int a, int b, int c, int d) {
x = one(a, b); //here is my problem
y = one(c, d); //here is my problem
cout << "made one two\n";
}
friend ostream &operator<<(ostream &, two);
};
ostream &operator<<(ostream &os, two a) {
return os << a.x << a.y;
}
int main() {
two t1, t2(4, 2, 8, 3);
cout << t1 << t2;
one t3(5, 10), t4;
cout << t3 << t4;
return 0;
}
Upvotes: 1
Views: 9969
Reputation: 837
Current approach works only if you have a default constructor in one class. It is better to initialize members in constructor initialization list:
two(int a, int b, int c, int d)
: x(a,b), y(c,d)
{
cout << "made one two\n";
}
Upvotes: 2
Reputation: 3509
x = one(a, b); //here is my problem
y = one(c, d); //here is my problem
What this code does is that it calls the constructor of the class one
and assigns the newly created instance of this class to the variables x
and y
.
The constructor of class one
is in line 9.
Upvotes: 2
Reputation: 4912
from the line x = one(a, b);
it jumps to line
one(int a, int b)
and executes the parameterized constructor of one
same for line y = one(c, d);
Upvotes: 3