Reputation: 813
The following are the steps I would like to have:
The following is my first attempt to write AppleScript:
tell application "Xcode"
tell project "iphone_manual_client"
debug
end tell
close project "iphone_manual_client"
end tell
This only works when xcode has this project opened. I would like to have the project to be opened only when it is necessary to do so.
Can any AppleScript gurus out there points me to the right direction? Thanks.
-chuan-
Upvotes: 13
Views: 10858
Reputation: 20799
Since debugging can take an arbitrary amount of time, you probably want a "with timeout of seconds" / "end timeout" block around the debug message.
Upvotes: 2
Reputation: 813
I think I managed to solve it. The following is the AppleScript:
tell application "Xcode"
open "Users:chuan:Desktop:iphone_manual_client:iphone_manual_client.xcodeproj"
tell project "iphone_manual_client"
clean
build
(* for some reasons, debug will hang even the debug process has completed.
The try block is created to suppress the AppleEvent timeout error
*)
try
debug
end try
end tell
quit
end tell
The path has to be in format of ":" instead of "/". The only problem now is that after the debug console has done its job, AppleScript seems to "hang" as though waiting for something to happen. I need to do more research on AppleScript to know what is wrong with the script.
Upvotes: 13
Reputation: 79870
I'm not sure about AppleScript but you can compile it from command line, without opening xcode ide, like this:
xcodebuild -configuration Debug -target WhatATool -project WhatATool.xcodeproj
Where configuration is obvious option, target is the name in Target list of xcode and the project name at the end.
Upvotes: 4