Reputation: 4974
I need to define the type of passed variable as an generic object, how?
Tried:
public function set($service = null, (object) $instance) {
[..]
}
Can stdClass
help? How?
Thanks!
Upvotes: 0
Views: 355
Reputation: 2864
Gabriel,
if what you want to do is check if the variable is an object, you could do this:
public function set($service = null, $instance) {
if (!is_object($instance)) return null; //or whatever
[..]
}
What are you trying to prevent with that? With your declaration, you would get an exception if the variable is not an object (it will not cast it).
Upvotes: 0
Reputation: 78991
No, the object has to be some class. You can give the any class name as object's type
public function set($service = null, ClassName $instance) {
//now the instance HAS to be the object of the class
}
Or a basic trick would be to create a basic class yourself
Class GenericObject {}
$myobj = new GenericObject();
$myobj -> myCustomVar = 'my custom var';
//Now send it
public function set($service = null, GenericObject $instance) {
[...]
}
Upvotes: 1
Reputation: 254924
Nope, in php all classes aren't derive from the common ancestor.
So doubtfully you can use current php's implementation to state "object of any class"
Upvotes: 1