CODEWITHSUNDEEP
c++
user949814
user949814

Reputation:

How do you print the address of an object in C++?

If I have the following basic C++ program:

#include <iostream>
using namespace std;

class CRectangle {
    int x, y;
  public:
    void set_values (int,int);
    int area () {return (x*y);}
};

void CRectangle::set_values (int a, int b) {
  x = a;
  y = b;
}

int main () {
  CRectangle rect;
  rect.set_values (3,4);
  cout << "area: " << rect.area() <<endl;
  cout <<&rect<<endl;
  cin.get();
  return 0;
}

is the last print statement printing the address of the variable rect or the address of the object? are they the same? or are they the same?

Upvotes: 0

Views: 308

Answers (4)

Anzurio
Anzurio

Reputation: 17014

rect is just an identifier for an object in the stack. In this case, an instance of CRectangle.

By calling &rect, you'll be getting the address, in the stack, where the object resides.

Upvotes: 0

skimon
skimon

Reputation: 1179

There is no such thing as an address of a Class if thats what you mean? &CRectangle does not exist , only an address of an instance of the class (&rect) exists. No memory is occupied by the Class definition itself.

Upvotes: 3

Attila
Attila

Reputation: 28762

The variable rect is an object of CRectablge, so there is no difference between the address of the variable and the object in this case.

Upvotes: 0

Kevin Anderson
Kevin Anderson

Reputation: 7010

They are the same. It's printing the address of rect which is the same as the address of the object. Rect is on the stack, and thus the entire object is as well.

Upvotes: 4

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