CODEWITHSUNDEEP
phpjavascriptexpression
Ronald
Ronald

Reputation: 322

Regular expressions that removes only first "/"

I'm new to Regular expressions and can't seem to find out how I have to solve this:

I need a regular expressions that "allows" only numbers, letters and /. I wrote this:

/[^a-zA-Z0-9/]/g

I think it's possible to strip the first / off, but don't know how.

so #/register/step1 becomes register/step1

Who knows how I could get this result?

Thanks!

Upvotes: 3

Views: 94

Answers (3)

Tomasz Gawel
Tomasz Gawel

Reputation: 8520

"/register/step1".match(/[a-zA-Z0-9][a-zA-Z0-9/]*/); // ["register/step1"]

\w is Equivalent to [^A-Za-z0-9_], so:

"/register/step1".match(/\w[\w/]*/); // ["register/step1"]

Upvotes: 1

orourkek
orourkek

Reputation: 2101

edit: Don't know why i didn't suggest this first, but if you're simply enforcing the pattern rather than replacing, you could just replace that slash (if it exists) before checking the pattern, using strpos(), substr(), or something similar. If you are using a preg_replace() already, then you should look at the examples on the function docs, they are quite relevant

Upvotes: 0

kennebec
kennebec

Reputation: 104790

You can use a non-global match, if the pattern is contiguous in the string:

var rx=/(([a-zA-Z0-9]+\/*)+)/;

var s='#/register/step1';

var s1=(s.match(rx) || [])[0];


alert(s1)>>>  returned value: (String) "register/step1"

Upvotes: 2

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