CODEWITHSUNDEEP
c++overloading
orangepixel
orangepixel

Reputation: 115

ambigious functions in c++

I would like to know why these declarations won't work(are not compatible)

void f(int); //p1
void f(const int);//p2
void f(int &);//p3
void f(const int &);//p4

If I understood well, the compiler won't find a difference between (int &) and (const int &) and if I write f(12) it won't be able to choose between the two first declarations.. Am I right?

Upvotes: 5

Views: 157

Answers (1)

Xeo
Xeo

Reputation: 131829

p3 and p4 are perfectly unambiguous and distinguishable, p1 and p2 are not. (And of course p1/p2 are distinguishable from p3 and p4.)

The reason is that top-level const on a value parameter is not detectable and infact useless on a declaration. You can for example do the following:

void foo(int x); // declaration
// ...
void foo(const int x){
  // definition/implementation
}

The const here is an implementation detail that's not important for the caller, since you make a copy anyways. That copy is also the reason why it's not distinguishable from just int, from the callers side it's exactly the same.

Note that const int& r does not have a top-level const, it's the reference that refers to a constant integer (references are always constant). For pointers, which may be changed if not declared const, see also this question for where to put const.

Upvotes: 7

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