Reputation: 24423
How can I delete all of the lines in a CSV file which contain more than 3 characters in the second column? E.g.:
cave,ape,1
tree,monkey,2
The second line contains more than 3 characters in the second column, so it will be deleted.
Upvotes: 3
Views: 2380
Reputation: 7640
This is a filter script for your type of data. It assumes your data is in utf8
#!/bin/bash
function px {
local a="$@"
local i=0
while [ $i -lt ${#a} ]
do
printf \\x${a:$i:2}
i=$(($i+2))
done
}
(iconv -f UTF8 -t UTF16 | od -x | cut -b 9- | xargs -n 1) |
if read utf16header
then
px $utf16header
cnt=0
out=''
st=0
while read line
do
if [ "$st" -eq 1 ] ; then
cnt=$(($cnt+1))
fi
if [ "$line" == "002c" ] ; then
st=$(($st+1))
fi
if [ "$line" == "000a" ]
then
out=$out$line
if [[ $cnt -le 3+1 ]] ; then
px $out
fi
cnt=0
out=''
st=0
else
out=$out$line
fi
done
fi | iconv -f UTF16 -t UTF8
Upvotes: 2
Reputation: 26096
No one has supplied a sed
answer yet, so here it is:
sed -e '/^[^,]*,[^,]\{4\}/d' animal.csv
And here's some test data.
>animal.csv cat <<'.'
cave,ape,0
,cat,1
,orangutan,2
large,wolf,3
,dog,4,happy
tree,monkey,5,sad
.
And now to test:
sed -i'' -e '/^[^,]*,[^,]\{4\}/d' animal.csv
cat animal.csv
Only ape, cat and dog should appear in the output.
Upvotes: 2
Reputation: 3417
You can use this command:
grep -vE "^[^,]+,[^,]{4,}," test.csv > filtered.csv
Breakdown of the grep syntax:
-v = remove lines matching
-E = extended regular expression syntax (also -P is perl syntax)
bash stuff:
> filename = overwrite/create a file and fill it with the standard out
Breakdown of the regex syntax:
"^[^,]+,[^,]{4,},"
^ = beginning of line
[^,] = anything except commas
[^,]+ = 1 or more of anything except commas
, = comma
[^,]{4,} = 4 or more of anything except commas
And please note that the above is simplified and would not work if the first 2 columns contained commas in the data. (it does not know the difference between escaped commas and raw ones)
Upvotes: 2