CODEWITHSUNDEEP
python
meruru
meruru

Reputation: 33

Getting part of URL after redirect

OK, here's basically what I am trying to do:

The URL http://anidb.net/perl-bin/animedb.pl?show=animelist&adb.search="Cowboy Bebop"&do.search=search redirects to http://anidb.net/perl-bin/animedb.pl?show=anime&aid=23

Let's say I want to write down the ID (23, in that example) in a XML file.

Upvotes: 1

Views: 155

Answers (3)

Wessie
Wessie

Reputation: 3520

Unrelated to the actual coding question. But you might want to use the AniDB search data instead of querying their website.

Upvotes: 0

Fenikso
Fenikso

Reputation: 9451

Result of urlopen has method geturl which provides the redirect information. Then you can parse it using regular expression.

import urllib2
import re

url = 'http://anidb.net/perl-bin/animedb.pl?show=animelist&adb.search=%22Cowboy%20Bebop%22&do.search=search'
headers = {"User-agent": "Mozilla/5.0"}
request = urllib2.Request(url, None, headers)
result = urllib2.urlopen(request)
r =  re.search("aid=(\d+)", result.geturl())
print r.group(1)

Upvotes: 1

Kasapo
Kasapo

Reputation: 5374

Do this:

var uri = window.location.href
var params = uri.split("?")[1].split("&");

args = {};
for(var i=0; i<params.length; i++) {
    p = params[i].split("=");
    args[p[0]] = p[1];
}
alert(args['aid']);

[EDIT: Saw python tag]

So, in python, if you have a URL, you could split it very similarly:

uri = "http://anidb.net/perl-bin/animedb.pl?show=anime&aid=23"
params = uri.split('?')[1].split('&')

args={}
for kv in params:
     p = kv.split('=')
     args[p[0]] = p[1]

But again, I have no idea where python comes into play in your question, as it seems the scripts getting hit are perl.

Upvotes: 0

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