Reputation: 359
I have this XAML code that throws an exception (It just says it threw it, no name).
I googled around and found http://social.msdn.microsoft.com/Forums/en/wpf/thread/cfb159dc-d58e-41c2-81b5-c52e1272c0ce. Which says that any change made on a used property throws an exception.
So is it impossible to set a trigger in the <Control.Style>
?
I'm sure it's a very noob mistake as I am learning this technology.
XAML code
<Window x:Class="Triggers.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Button>
<Button.Style>
<Style TargetType="Button">
<Style.Triggers>
<Trigger Property="IsMouseOver" >
<Setter Property="Opacity" Value="0.7" />
</Trigger>
</Style.Triggers>
</Style>
</Button.Style>
Meow
</Button>
</Grid>
Upvotes: 0
Views: 87
Reputation: 45155
It's because you haven't told the trigger what value the property IsMouseOver should have?
Try this:
<Trigger Property="IsMouseOver" Value="True">
The thing to remember is the "IsMouseOver" is a property, not an event. So it can be either true or false and you need to tell WPF which state your trigger applies to.
Upvotes: 2