CODEWITHSUNDEEP
javascript
user1330271
user1330271

Reputation: 2691

passing function as parameter

I got two functions, passing one of then as parameter, like:

var a = function(f)
{
  // some code
  f();
};

var b = function()
{
};

a(b); // works great, the function a is executed, then the function b is executed

Now I need to extend it to tree functions, like:

var a = function(f)
{
  // some code
  f();
};

var b = function(f)
{
  // some code
  f();
};

var c = function()
{
};

a(b(c)); // but it does not work. b(c) words like a method and get executed right on the instruction.

How can i do that?

Upvotes: 0

Views: 105

Answers (4)

Tejs
Tejs

Reputation: 41256

It sounds like you want to use a callback kind of pattern. Instead of simply passing along the results of the functions, you would do something like so:

var a = function(callback)
{
    // Do Stuff
    callback();
}

var b = function(callback)
{
    // Do Stuff
    callback();
}

var c = function() { }

Your code would end up looking like so:

a(function()
{
   b(function()
   {
       c();
   });
});

Effectively, you pass along another function to execute after the method finished. In the above scenario, I simply supply two anonymous functions as the callback arguments.

Upvotes: 2

FishBasketGordo
FishBasketGordo

Reputation: 23142

One way would be to use an anonymous function:

a(function() { b(c); });

Upvotes: 1

bigblind
bigblind

Reputation: 12887

function a(f){
  // code
  f()
}
function b(f){
  // code
  a(f())
}
function c(){
  //code
}

b(c);

Upvotes: 1

user1233508
user1233508

Reputation:

Pass a wrapper function that executes b(c):

a(function() {
    b(c);
});

Upvotes: 3

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