CODEWITHSUNDEEP
javascriptdecimalrounding
Eric
Eric

Reputation: 2231

Truncate/round whole number in JavaScript?

For a script I'm writing, I need display a number that has been rounded, but not the decimal or anything past it. I've gotten down to rounding it to the third place, but I'm not sure how to go about just dropping the decimal and everything past it, as it doesn't seem like JavaScript has a substr function like PHP does.

Any recommendations?

Upvotes: 70

Views: 114779

Answers (6)

Travis Pessetto
Travis Pessetto

Reputation: 3298

I'll add my solution here. We can use floor when values are above 0 and ceil when they are less than zero:

function truncateToInt(x)
{
    if(x > 0)
    {
         return Math.floor(x);
    }
    else
    {
         return Math.ceil(x);
    }
 }

Then:

y = truncateToInt(2.9999); // results in 2
y = truncateToInt(-3.118); //results in -3

Notice: This answer was written when Math.trunc(x) was fairly new and not supported by a lot of browsers. Today, modern browsers support Math.trunc(x).

Upvotes: 14

Asad Manzoor
Asad Manzoor

Reputation: 1465

Math.trunc() function removes all the fractional digits.

For positive number it behaves exactly the same as Math.floor():

console.log(Math.trunc(89.13349)); // output is 89

For negative numbers it behaves same as Math.ceil():

console.log(Math.trunc(-89.13349)); //output is -89

Upvotes: 1

Ry-
Ry-

Reputation: 224867

If you have a string, parse it as an integer:

var num = '20.536';
var result = parseInt(num, 10);  // 20

If you have a number, ECMAScript 6 offers Math.trunc for completely consistent truncation, already available in Firefox 24+ and Edge:

var num = -2147483649.536;
var result = Math.trunc(num);  // -2147483649

If you can’t rely on that and will always have a positive number, you can of course just use Math.floor:

var num = 20.536;
var result = Math.floor(num);  // 20

And finally, if you have a number in [−2147483648, 2147483647], you can truncate to 32 bits using any bitwise operator. | 0 is common, and >>> 0 can be used to obtain an unsigned 32-bit integer:

var num = -20.536;
var result = num | 0;  // -20

Upvotes: 136

BlinkyTop
BlinkyTop

Reputation: 1144

Travis Pessetto's answer along with mozey's trunc2 function were the only correct answers, considering how JavaScript represents very small or very large floating point numbers in scientific notation.

For example, parseInt(-2.2043642353916286e-15) will not correctly parse that input. Instead of returning 0 it will return -2.

This is the correct (and imho the least insane) way to do it:

function truncate(number)
{
    return number > 0
         ? Math.floor(number)
         : Math.ceil(number);
}

Upvotes: 18

mozey
mozey

Reputation: 2292

Convert the number to a string and throw away everything after the decimal.

trunc = function(n) { return Number(String(n).replace(/\..*/, "")) }

trunc(-1.5) === -1

trunc(1.5) === 1

Edit 2013-07-10

As pointed out by minitech and on second thought the string method does seem a bit excessive. So comparing the various methods listed here and elsewhere:

function trunc1(n){ return parseInt(n, 10); }
function trunc2(n){ return n - n % 1; }
function trunc3(n) { return Math[n > 0 ? "floor" : "ceil"](n); }
function trunc4(n) { return Number(String(n).replace(/\..*/, "")); }

function getRandomNumber() { return Math.random() * 10; }

function test(func, desc) {
    var t1, t2;
    var ave = 0;
    for (var k = 0; k < 10; k++) {
        t1 = new Date().getTime();
        for (var i = 0; i < 1000000; i++) {
            window[func](getRandomNumber());
        }
        t2 = new Date().getTime();
        ave += t2 - t1;
    }
    console.info(desc + " => " + (ave / 10));
}

test("trunc1", "parseInt");
test("trunc2", "mod");
test("trunc3", "Math");
test("trunc4", "String");

The results, which may vary based on the hardware, are as follows:

parseInt => 258.7
mod      => 246.2
Math     => 243.8
String   => 1373.1

The Math.floor / ceil method being marginally faster than parseInt and mod. String does perform poorly compared to the other methods.

Upvotes: 10

gilly3
gilly3

Reputation: 91487

Use Math.floor():

var f = 20.536;
var i = Math.floor(f);  // 20

http://jsfiddle.net/J4UVV/1/

Upvotes: 1

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