CODEWITHSUNDEEP
pythonnumpymatplotlibscipy
HipsterCarlGoldstein
HipsterCarlGoldstein

Reputation: 1039

What does .shape[] do in "for i in range(Y.shape[0])"?

I'm trying to break down a program line by line. Y is a matrix of data but I can't find any concrete data on what .shape[0] does exactly.

for i in range(Y.shape[0]):
    if Y[i] == -1:

This program uses numpy, scipy, matplotlib.pyplot, and cvxopt.

Upvotes: 90

Views: 504916

Answers (6)

Levon
Levon

Reputation: 143022

shape is a tuple that gives you an indication of the number of dimensions in the array. So in your case, since the index value of Y.shape[0] is 0, your are working along the first dimension of your array.

From Link

 An array has a shape given by the number of elements along each axis:
 >>> a = floor(10*random.random((3,4)))

 >>> a
 array([[ 7.,  5.,  9.,  3.],
        [ 7.,  2.,  7.,  8.],
        [ 6.,  8.,  3.,  2.]])

 >>> a.shape
 (3, 4)

and http://www.scipy.org/Numpy_Example_List#shape has some more examples.

Upvotes: 11

ajay
ajay

Reputation: 53

shape() consists of array having two arguments rows and columns.

if you search shape[0] then it will gave you the number of rows. shape[1] will gave you number of columns.

Upvotes: 3

Drool
Drool

Reputation: 129

In python, Suppose you have loaded up the data in some variable train:

train = pandas.read_csv('file_name')
>>> train
train([[ 1.,  2.,  3.],
        [ 5.,  1.,  2.]],)

I want to check what are the dimensions of the 'file_name'. I have stored the file in train

>>>train.shape
(2,3)
>>>train.shape[0]              # will display number of rows
2
>>>train.shape[1]              # will display number of columns
3

Upvotes: 6

HeadAndTail
HeadAndTail

Reputation: 812

In Python shape() is use in pandas to give number of row/column:

Number of rows is given by:

train = pd.read_csv('fine_name') //load the data
train.shape[0]

Number of columns is given by 

train.shape[1]

Upvotes: 4

Wickkiey
Wickkiey

Reputation: 4632

shape is a tuple that gives dimensions of the array.. 

>>> c = arange(20).reshape(5,4)
>>> c
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11],
       [12, 13, 14, 15],
       [16, 17, 18, 19]])

c.shape[0] 
5

Gives the number of rows

c.shape[1] 
4

Gives number of columns

Upvotes: 48

unutbu
unutbu

Reputation: 879591

The shape attribute for numpy arrays returns the dimensions of the array. If Y has n rows and m columns, then Y.shape is (n,m). So Y.shape[0] is n.

In [46]: Y = np.arange(12).reshape(3,4)

In [47]: Y
Out[47]: 
array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11]])

In [48]: Y.shape
Out[48]: (3, 4)

In [49]: Y.shape[0]
Out[49]: 3

Upvotes: 148

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