Reputation: 59811
I would like to build a multi-index with two sequenced
views, where
I can remove values from only one view.
In code:
#include <boost/multi_index_container.hpp>
#include <boost/multi_index/sequenced_index.hpp>
#include <algorithm>
#include <iterator>
#include <vector>
using namespace boost::multi_index;
typedef multi_index_container<
int,
indexed_by<
sequenced<>,
sequenced<>
>
> container;
int main()
{
container c;
std::vector<int>
// complete
data = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10},
// only uneven
uneven_data;
std::copy_if(begin(data), end(data),
std::back_inserter(uneven_data),
[](int i) { return i % 2 != 0; });
container cont;
std::copy(begin(data), end(data), std::back_inserter(cont));
auto& idx0 = cont.get<0>();
auto& idx1 = cont.get<1>();
// remove all uneven from idx1
idx1.remove_if([](int i) { return i % 2 == 0; });
// behavior I would like to be true, but now both idx0 and idx1 are
// equal to uneven_data
assert(std::equal(begin(data), end(data), begin(idx0)));
assert(std::equal(begin(uneven_data), end(uneven_data), begin(idx1)));
return 0;
}
Is something like this possible with boost::multi_index
?
Upvotes: 1
Views: 933
Reputation: 1213
As I mentioned above, a more flexible (non-predicate based) approach using boost intrusive. Using two or more list hooks you can make one object participate in two or more sequences simultaneously.
#include <boost/intrusive/list.hpp>
#include <boost/foreach.hpp>
#include <algorithm>
#include <memory>
#include <iostream>
namespace intr = boost::intrusive;
template<class Value>
struct Sequence2
{
typedef intr::link_mode< intr::auto_unlink > AutoUnlinkMode;
typedef intr::list_member_hook< AutoUnlinkMode > SeqHook;
struct Node
{
Node( const Value& i ) : value(i) {}
operator Value&()
{
return value;
}
Value value;
SeqHook mainHook;
SeqHook hook0;
SeqHook hook1;
};
typedef intr::member_hook< Node, SeqHook,&Node::mainHook > UsingMainHook;
typedef intr::member_hook< Node, SeqHook,&Node::hook0 > UsingSeqHook0;
typedef intr::member_hook< Node, SeqHook,&Node::hook1 > UsingSeqHook1;
typedef intr::constant_time_size<false> NonConstantTimeSized;
typedef intr::list< Node, UsingMainHook, NonConstantTimeSized > NodesList;
typedef intr::list< Node, UsingSeqHook0, NonConstantTimeSized > Sequence0;
typedef intr::list< Node, UsingSeqHook1, NonConstantTimeSized > Sequence1;
NodesList nodes;
Sequence0 seq0;
Sequence1 seq1;
typename NodesList::iterator insert( const Value& item )
{
Node* node = new Node(item);
nodes.push_back( *node );
typename NodesList::iterator iter = nodes.end(); iter--;
seq0.push_back( *node );
seq1.push_back( *node );
return iter;
}
typename Sequence0::iterator iterator0( typename NodesList::iterator iter )
{
return seq0.iterator_to( *iter );
}
typename Sequence1::iterator iterator1( typename NodesList::iterator iter )
{
return seq1.iterator_to( *iter );
}
//! Erase from both sequences
void erase( typename NodesList::iterator at )
{
nodes.erase_and_dispose( at, std::default_delete<Node>() );
}
//! Erase from sequence 0
void erase( typename Sequence0::iterator at )
{
Node& n = *at;
assert( n.hook0.is_linked() );
if( ! n.hook1.is_linked() )
{
seq0.erase_and_dispose( at, std::default_delete<Node>() );
}
else
{
seq0.erase(at);
}
}
//! Erase from sequence 1
void erase( typename Sequence1::iterator at )
{
Node& n = *at;
assert( n.hook1.is_linked() );
if( ! n.hook0.is_linked() )
{
seq1.erase_and_dispose( at, std::default_delete<Node>() );
}
else
{
seq1.erase(at);
}
}
~Sequence2()
{
nodes.clear_and_dispose( std::default_delete<Node>() );
}
};
template< class T >
void show( Sequence2<T>& mseq, const std::string& comment )
{
std::cout << comment << "\nseq 0:\t";
BOOST_FOREACH( T& i, mseq.seq0 )
{
std::cout << i << " ";
}
std::cout << "\nseq 1:\t";
BOOST_FOREACH( T& i, mseq.seq1 )
{
std::cout << i << " ";
}
std::cout << "\n\n";
}
int main(void)
{
Sequence2< std::string > mseq;
mseq.insert( "." );
auto iterX = mseq.insert("X");
auto iterY = mseq.insert("Y");
auto iterZ = mseq.insert("Z");
mseq.insert(".");
mseq.insert(".");
show(mseq, "start" );
mseq.seq0.reverse();
show(mseq, "after reverse seq0");
mseq.erase( mseq.iterator0(iterY) );
show(mseq, "after erase Y in seq0");
// Update a value in both sequences
std::string& v = *iterZ;
v = "z";
show(mseq, "after modify Z in both");
mseq.erase( iterX );
show(mseq, "after erase X in both");
mseq.erase( iterY );
show(mseq, "after erase Y in both");
return 0;
}
Which produces:
start
seq 0: . X Y Z . .
seq 1: . X Y Z . .
after reverse seq0
seq 0: . . Z Y X .
seq 1: . X Y Z . .
after erase Y in seq0
seq 0: . . Z X .
seq 1: . X Y Z . .
after modify Z in both
seq 0: . . z X .
seq 1: . X Y z . .
after erase X in both
seq 0: . . z .
seq 1: . Y z . .
after erase Y in both
seq 0: . . z .
seq 1: . z . .
Upvotes: 0
Reputation: 1213
No. In a boost multi_index_container, the indices are coupled together as separate views of the same values. This is an important guarantee of boost multi_index_containers.
"Boost.MultiIndex allows for the specification of multi_index_containers comprised of one or more indices with different interfaces to the same collection of elements" (boost multi_index tutorial).
With two distinct sequenced<> indices you can re-arrange the order in two different ways, but they must both contain all values.
If you wish to view a subset of elements according to a boolean predicate (eg: value is odd), consider using boost::filter_iterator. This does not attempt to erase values in the container but instead skip them during iteration.
Alternatively, selection/filtering can be obtained by ordering, using a multi_index ordered_non_unique index with an appropriate key extractor.
For example, an ordered_non_unique index based on a key extractor: [](int i) { return i % 2; }
will place the odd and even values in distinct groups, so an iterator range to all odd values can be obtained using equal_range.
Upvotes: 2