Reputation: 5334
This might sound a bit confusing at first. But I have a table with data and I want to create duplicates of all the rows in this table. So, if i do:
SELECT *
FROM the_table
it lists all the data in this table. Now, i want to create a copy of all returned results, except for that I want to change data for one column (the date). This will make the new rows unique.
The reason I want to do this is because I want more data in this table since im building statistics out of it for testing purposes. So, if I have this:
**Column1 Column2 Column3**
abc aaa bbb
abcd aaaa bbbb
abcde aaaaa bbbbb
The table will now contain:
**Column1 Column2 Column3**
abc aaa bbb
abcd aaaa bbbb
abcde aaaaa bbbbb
abc aaa bbb_new
abcd aaaa bbbb_new
abcde aaaaa bbbbb_new
Upvotes: 3
Views: 131
Reputation: 156
To duplicate rows (all columns) you simply could use
insert into tblname
select * from tblname
to change one column that can be modified to
insert into tblname
select column1, column2, 'fixedvalueforcolumn3' from tblname
But you need a unique value for column 3, so you have to change 'fixedvalueforcolumn3' to a function that will generate some random (unique) value (date in your case) for column 3
insert into tblname
select column1, column2, generateRandomValue() from tblname
Hope that will help you
Upvotes: 2
Reputation: 19346
Assuming there is an identity column (ID) you might generate dates (A_Date) like this:
insert into the_table (Column1, Column2, A_Date)
select Column1, Column2, A_Date + (rand(ID) - 0.5) * 100
from the_table
Upvotes: 2
Reputation: 2985
Consider making a Cartesian Join on your table. This will give you way more data quickly :)
Upvotes: 3
Reputation: 204746
insert into your_table
select col1, col2, concat(col3, '_new') from your_table
Upvotes: 6
Reputation: 70718
INSERT INTO TABLEDUPLICATES
SELECT * FROM the_table
SELECT * FROM TABLEDUPLICATES UNION
SELECT * FROM the_table
Upvotes: 2