Reputation: 59
I know it seems like a daft question but I am getting synatx error var imagename = ;
. in the code below.
var imagename = <?php if (isset($_SESSION['imagename'])) echo json_encode($_SESSION['imagename']); ?>;
var imagename is a javascript variable but why am I getting this error? is it because ; is in the wrong place or am I messing a ; or have I added to many ;. I just can't seem to figure it out.
Thanks
Upvotes: 1
Views: 116
Reputation:
Perhaps you are looking for something like this:
var imagename = <?php echo json_encode(isset($_SESSION['imagename']) ? $_SESSION['imagename'] : null); ?>
See http://php.net/ternary#language.operators.comparison.ternary for more info on how the ternary operator works.
Upvotes: 2
Reputation: 360782
You have no else clause, so if that session variable isn't set, you end up generating your empty assignment.
var imagename = <?php if (isset($_SESSION['imagename'])) { echo json_encode($_SESSION['imagename']); } else { echo "''"; } ?>;
Upvotes: 2
Reputation: 20235
The error is probably occuring when $_SESSION['imagename']
does not exist. You should add an else clause for when this happens.
Upvotes: 0