CODEWITHSUNDEEP
phpsyntaxsedquoteslibssh2
Jeremy Sayers
Jeremy Sayers

Reputation: 637

Escaped Quotes in PHP for Sed Command

I have the following php code

if (!($stream = ssh2_exec($con, 'sed -i \'s/motd=A Minecraft Server/motd=\'.$name.\'s     Server/g\' /home/servers/runner15/server.properties
'))) {

But when I run it instead of replacing the text "motd=A Minecraft Server" to "motd=runner15s Server" it Changes it to motd=..s Server

It's something todo with escaping the quotes

Oh by the way $name holds runner15

Upvotes: 0

Views: 286

Answers (2)

Marc B
Marc B

Reputation: 360792

Basic PHP strings... ' strings do NOT interpolate variables, so your sed command contains a literal $, n, a, m, e, etc... That'll be interpreted as a non-existent shell varaible on the remote server, and expand to an empty string.

[...snip...]otd=A Minecraft Server/motd=\''.$name.'\'s [..snip...]
                                          ^-------^--- 'exit' the string in your client-side PHP

Upvotes: 2

alganet
alganet

Reputation: 2547

Try escapeshellcmd before ssh2_exec. http://www.php.net/manual/en/function.escapeshellcmd.php

Upvotes: 0

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