Reputation: 1844
I need to fetch the records based on a 'like' match against a set of records,
The below query im using is not working . Does anyone knows what's wrong with the query?
sqlCommand.CommandText =String.Format("SELECT * FROM Customer" +
" WHERE (Name like @Name)","'%" +searchString.Trim()+"%'");
sqlCommand.Parameters.AddWithValue("Name", searchString);
This query isnt fetching the desired records.
I'm getting the following error while running the above snippet:
Must declare the scalar variable "@Name".
Upvotes: 6
Views: 43034
Reputation: 1
If Not con.State = ConnectionState.Open Then con.Open() End If
Try
Dim cmd As New OleDbCommand("UPDATE med_records SET Medicine=@Medicine,Dosage=@Dosage,Format=@Format,Expiration_date=@Expiration_date,Quantity=@Quantity where M_id=@M_id", con)
cmd.Parameters.AddWithValue("@Medicine", txtMedicine.Text)
cmd.Parameters.AddWithValue("@Dosage", txt_Dosage.Text)
cmd.Parameters.AddWithValue("@Format", txt_Format.Text)
cmd.Parameters.AddWithValue("@Expiration_date", txt_Expirationdate.Text)
cmd.Parameters.AddWithValue("@Quantity", NumericUpDown1.Text)
cmd.Parameters.AddWithValue("@M_id", txt_M_id.Text)
cmd.ExecuteNonQuery()
MsgBox("Update data")
con.Close()
Catch ex As Exception
MsgBox(ex.Message)
End Try
Upvotes: -3
Reputation:
What happens this way?
sqlCommand.CommandText = "SELECT * FROM Customer WHERE Name LIKE @Name;";
sqlCommand.Parameters.AddWithValue("@Name", "%" + searchString + "%");
You could also code it as follows to avoid all the wildcard formatting in the first place:
sqlCommand.CommandText = "SELECT * FROM Customer WHERE CHARINDEX(@Name, Name) > 0;";
sqlCommand.Parameters.AddWithValue("@Name", searchString);
If you're going to insist on doing it the unsafe way, at the very least double-up any single quotes found in searchString
, e.g.
searchString.Replace("'", "''")
Upvotes: 14
Reputation: 107247
String.Format needs a placeholder, like {0} {1} etc.
sqlCommand.CommandText = "SELECT * FROM Customer WHERE Name LIKE @Name;";
sqlCommand.Parameters.AddWithValue("@Name", String.Format("%{0}%", searchString));
Upvotes: 1