Reputation: 381
Folks, I just spent a good amount of time trying to look this up -- I ought to be missing something basic.
I have a python object, all I want to do is to insert this object in mondodb.
This is what I have:
from pymongo import Connection
import json
conn = Connection()
db = conn.cl_database
postings = db.postings_collection
class Posting(object):
def __init__(self, link, found=None, expired=None):
self.link = link
self.found = found
self.expired = expired
posting = Posting('objectlink1')
value = json.dumps(posting, default=lambda x:x.__dict__)
postings.insert(value)
throws this error:
Traceback (most recent call last):
File "./mongotry.py", line 21, in <module>
postings.insert(value)
File "build/bdist.macosx-10.7-intel/egg/pymongo/collection.py", line 302, in insert
File "build/bdist.macosx-10.7-intel/egg/pymongo/database.py", line 252, in _fix_incoming
File "build/bdist.macosx-10.7-intel/egg/pymongo/son_manipulator.py", line 73, in transform_incoming
TypeError: 'str' object does not support item assignment
Seems like it is because json.dumps() returns a string.
Now if I do do a loads of the value before inserting it works fine:
posting = Posting('objectlink1')
value = json.dumps(posting, default=lambda x:x.__dict__)
value = json.loads(value)
postings.insert(value)
What is the most straight-forward to do this?
Thanks!
Upvotes: 8
Views: 26631
Reputation: 92559
You are misusing the insert method for the collection. Review here: http://api.mongodb.org/python/current/api/pymongo/collection.html#pymongo.collection.Collection.insert
What you need to be inserting is a document. It should be a dict with keys and values. Simply trying to insert a string is not appropriate. json.dumps returns a string in json format. If you are just dumping it to get a dict then the json step is not necessary.
Insert exactly how your documents should look:
postings.insert({"key":"value"})
Or convert your class instance directly into the dict you want to store as a doc and then insert it. It works with your json.dumps.loads() because that ultimately does give you a dict.
Upvotes: 3
Reputation: 8231
What is value
in your initial code?
It should be dict
not class instance
This should work:
postings.insert(posting.__dict__)
Upvotes: 17