CODEWITHSUNDEEP
javascripttogglejquery
Cyclone
Cyclone

Reputation: 15259

Toggle show/hide on click with jQuery

I got a div element, so when I click on it, another div which is hidden by default is sliding and showing, here is the code for the animation itself:

$('#myelement').click(function(){
     $('#another-element').show("slide", { direction: "right" }, 1000);
});

How can I make that so when I click on the #myelement one more time (when the element is showed already) it will hide the #another-element like this:

$('#another-element').hide("slide", { direction: "right" }, 1000);?

So basicly, it should work exactly like a slideToggle but with the show/hide functions. Is that possible?

Upvotes: 50

Views: 339259

Answers (7)

vijayabalan
vijayabalan

Reputation: 99

<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js</script>        <script>
$(document).ready(function(){
  $("button").click(function(){
    $("p").toggle();
  });
});
</script>
</head>
<body>
<p>Welcome !!!</p>
<button>Toggle between hide() and show()</button>
</body>
</html>

Upvotes: 1

Adil
Adil

Reputation: 148110

The toggle-event is deprecated in version 1.8, and removed in version 1.9

Try this...

$('#myelement').toggle(
   function () {
      $('#another-element').show("slide", {
          direction: "right"
      }, 1000);
   },
   function () {
      $('#another-element').hide("slide", {
          direction: "right"
      }, 1000);
});

Note: This method signature was deprecated in jQuery 1.8 and removed in jQuery 1.9. jQuery also provides an animation method named .toggle() that toggles the visibility of elements. Whether the animation or the event method is fired depends on the set of arguments passed, jQuery docs.

The .toggle() method is provided for convenience. It is relatively straightforward to implement the same behavior by hand, and this can be necessary if the assumptions built into .toggle() prove limiting. For example, .toggle() is not guaranteed to work correctly if applied twice to the same element. Since .toggle() internally uses a click handler to do its work, we must unbind click to remove a behavior attached with .toggle(), so other click handlers can be caught in the crossfire. The implementation also calls .preventDefault() on the event, so links will not be followed and buttons will not be clicked if .toggle() has been called on the element, jQuery docs

You toggle between visibility using show and hide with click. You can put condition on visibility if element is visible then hide else show it. Note you will need jQuery UI to use addition effects with show / hide like direction.

Live Demo

$( "#myelement" ).click(function() {     
    if($('#another-element:visible').length)
        $('#another-element').hide("slide", { direction: "right" }, 1000);
    else
        $('#another-element').show("slide", { direction: "right" }, 1000);        
});

Or, simply use toggle instead of click. By using toggle you wont need a condition (if-else) statement. as suggested by T.J.Crowder.

Live Demo

$( "#myelement" ).click(function() {     
   $('#another-element').toggle("slide", { direction: "right" }, 1000);
});

Upvotes: 65

lakshmi priya
lakshmi priya

Reputation: 159

You can use .toggle() function instead of .click()....

Upvotes: 0

Pranay Rana
Pranay Rana

Reputation: 176886

Make use of jquery toggle function which do the task for you

.toggle() - Display or hide the matched elements.

$('#myelement').click(function(){
      $('#another-element').toggle('slow');
  });

Upvotes: 30

Chaitanya Voleti
Chaitanya Voleti

Reputation: 1

$(document).ready( function(){
  $("button").click(function(){
    $("p").toggle(1000,'linear');
  });
});

Live Demo

Upvotes: -3

CSS Guy
CSS Guy

Reputation: 1984

this will work for u

   $("#button-name").click(function(){
        $('#toggle-id').slideToggle('slow');
    });

Upvotes: 4

Abubakar Shams
Abubakar Shams

Reputation: 149

You can use this code for toggle your element var ele = jQuery("yourelementid"); ele.slideToggle('slow'); this will work for you :)

Upvotes: 0

Related Questions