CODEWITHSUNDEEP
shellsed
ksuralta
ksuralta

Reputation: 17156

sed whole word search and replace

How do I search and replace whole words using sed?

Doing

sed -i 's/[oldtext]/[newtext]/g' <file>

will also replace partial matches of [oldtext] which I don't want it to do.

Upvotes: 157

Views: 151602

Answers (5)

fzbd
fzbd

Reputation: 507

For a posix compliant alternative, consider replacing word boundary matches (\b) by an expanded equivalent ([^a-zA-Z0-9]), also taking into account occurrences at start of line (^) and end of line ($).

However, this quickly becomes impractical if you want to support repeated occurrences of the word to replace (e.g. oldtext oldtext). sed --posix doesn't recognize expressions such as \(^\|[^a-zA-Z0-9]\), and you can't make use of lookarounds.

It seems we have to explictly match all possible cases. Here's a solution to replace mint with minty:

echo 'mint 0mint mint mint0 mint__mint mint__ mint_ -mint mint mint mint_ mint -mint- mint mint mintmint mint' \
  | sed --posix '   
s/^mint$/minty/g;
s/^mint\([^a-zA-Z0-9]\)/minty\1/g;
s/\([^a-zA-Z0-9]\)mint$/\1minty/g;
s/\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)/\1minty\2minty\3minty\4/g;
s/\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)/\1minty\2minty\3/g;
s/\([^a-zA-Z0-9]\)mint\([^a-zA-Z0-9]\)/\1minty\2/g;
'
# minty 0mint minty mint0 minty__minty minty__ minty_ -minty minty minty minty_ minty -minty- minty minty mintmint minty

Upvotes: 1

Larry Gerndt
Larry Gerndt

Reputation: 1925

On Mac OS X, neither of these regex syntaxes work inside sed for matching whole words

  • \bmyWord\b
  • \<myWord\>

Hear me now and believe me later, this ugly syntax is what you need to use:

  • /[[:<:]]myWord[[:>:]]/

So, for example, to replace mint with minty for whole words only:

  • sed "s/[[:<:]]mint[[:>:]]/minty/g"

Source: re_format man page

Upvotes: 171

Mitch Wheat
Mitch Wheat

Reputation: 300837

Use \b for word boundaries:

sed -i 's/\boldtext\b/newtext/g' <file>

Upvotes: 21

Arun
Arun

Reputation: 20403

In one of my machine, delimiting the word with "\b" (without the quotes) did not work. The solution was to use "\<" for starting delimiter and "\>" for ending delimiter.

To explain with Joakim Lundberg's example:

$ echo "bar embarassment" | sed "s/\<bar\>/no bar/g"
no bar embarassment

Upvotes: 9

Joakim Lundborg
Joakim Lundborg

Reputation: 11210

\b in regular expressions match word boundaries (i.e. the location between the first word character and non-word character):

$ echo "bar embarassment" | sed "s/\bbar\b/no bar/g"
no bar embarassment

Upvotes: 211

Related Questions