CODEWITHSUNDEEP
javaencryptionblock-cipher
One Two Three
One Two Three

Reputation: 23497

IllegalBLockSizeException when decrypting

I wrote an encrypt and a decrypt function. The encrypt works fine, but I always get IllegalBlockSizeException in the decrypt.

public static String aes_encrypt (String text, String key) 
{
    SecretKey skey = new SecretKeySpec(key.getBytes(), "AES"); 
    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding", "SunJCE");
    cipher.init(Cipher.ENCRYPT_MODE, skey);

    return new String((cipher.doFinal(text.getBytes())));

}

And here's the decrypt function:

public static String aes_decrypt (String text, String key) 
{

    SecretKey skey = new SecretKeySpec(key.getBytes(), "AES"); 
    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding", "SunJCE");
    cipher.init(Cipher.DECRYPT_MODE, skey);

    return new String((cipher.doFinal(text.getBytes())));
}

Here's the simple main method that tests this:

public static void main (String args[])
{
    String text = "Hello, world!";
    String key = "nv93h50sk1zh508v";
    String en, de;

    System.out.println("Text: " + text);
    System.out.println("Encrypted: " + (en = aes_encrypt(text, key)) 
            + " length = " + en.length());
    System.out.println("Decrypted: " + (de = aes_decrypt(en, key)));
}

Does anyone know how to "pad" the encrypted string properly so that I can decrypt it? (I tried padding the string with 0 until the length is a multiple of 16, but got something like string not properly padded.)

Thanks

Upvotes: 1

Views: 284

Answers (1)

David M
David M

Reputation: 72880

I think the problem is in your using the String constructor. This is converting to string using a text encoding mechanism, which may not preserve every value in the byte array - unsupported ones in the system default encoding may be discarded, leaving the encoded data shorter than it should be. If you want a string representation, convert to hex or base 64 encoding instead. And reverse whatever encoding you use here at the start of the decryption method.

It's not a padding issue - the encryption call will pad this fine, you are short of bytes because of your means of encoding the byte array to a string.

You'll find some base 64 instructions in answers to this SO question.

Upvotes: 2

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