Reputation: 187499
I want to replace the following Mozilla-specific CSS rule:
background: -moz-linear-gradient(center top , #F5F5F5, #E4E4E4);
with an equivalent rule that uses the standard linear-gradient
instead. In other words, how can I complete the following rule so that it has the same effect (in Firefox) as the rule above
background: linear-gradient /* what goes here? */
Upvotes: 0
Views: 336
Reputation: 55382
center
is not part of the linear gradient specification. (I don't know why it's ignored rather than being a CSS error.) The most up-to-date syntax supported by Firefox is -moz-linear-gradient(to bottom, #F5F5F5, #E4E4E4);
however as far as I know the specification hasn't reached CR status so this could still change.
Upvotes: 0
Reputation: 41
You could also use some gradient generators if you are having some difficulties or just for speeding up the process.
Examples:
http://www.colorzilla.com/gradient-editor/
http://westciv.com/tools/gradients/
http://gradients.glrzad.com/
Upvotes: 1
Reputation: 11
This is how I handle all gradients for all browsers, I hope this helps;
background: -moz-linear-gradient(top, rgba(0,0,0,0.65) 0%, rgba(0,0,0,0) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.65)), color-stop(100%,rgba(0,0,0,0))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0.65) 0%,rgba(0,0,0,0) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0.65) 0%,rgba(0,0,0,0) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0.65) 0%,rgba(0,0,0,0) 100%); /* IE10+ */
background: linear-gradient(top, rgba(0,0,0,0.65) 0%,rgba(0,0,0,0) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6000000', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
Upvotes: 1