AllTooSir
AllTooSir

Reputation: 49372

Inner class and local variables

Why do I need to declare a local variable as final if my Inner class defined within the method needs to use it ?

Example :

class MyOuter2 {

private String x = "Outer2";

void doStuff() {
    final String y = "Hello World";

    final class MyInner {

        String z = y;

        public void seeOuter() {
            System.out.println("Outer x is "+x);
            System.out.println("Local variable is "+y);
            MyInner mi = new MyInner();
            mi.seeOuter();
        }
    }
}

}

Why the String y needs to be a final constant ? How does it impact ?

Upvotes: 14

Views: 13546

Answers (6)

Vishal
Vishal

Reputation: 124

According to Java memory model use of final variable guarantees that the final variable are always initialized. We get error when we try to use local variable without initialization. using final guarantees the inner class that local variable which is been used is initialized.

Upvotes: 0

charles_ma
charles_ma

Reputation: 786

It's because the inner class inside a function actually makes a copy of the local variable because local variable may be destroyed after the function call while the instance of the local class still exists. To make the two copies of the local variable always have the same value(to make them seem identical), you have to declare the variable as final.

Upvotes: 9

Martijn Courteaux
Martijn Courteaux

Reputation: 68847

I think this is to prevent that the programmer would make mistakes. This way, the compiler reminds the programmer that the variable will not be accessible anymore when you leave that method. This is critical with looping. Imagine this code:

public void doStuff()
{
    InnerClass cls[] = new InnerClass[100];
    for (int i = 0; i < 100; ++i)
    {
        cls[i] = new InnerClass()
        {
            void doIt()
            {
                System.out.println(i);
            }
        };
    }
}

When the doIt() method is called, what will be printed? i changed while looping. To prevent that confusion, you have to copy the variable to a local variable or create the variable final, but then you will be unable to loop.

Upvotes: 3

mprabhat
mprabhat

Reputation: 20323

Local variables always live on the stack, the moment method is over all local variables are gone.

But your inner class objects might be on heap even after the method is over (Say an instance variable holds on to the reference), so in that case it cannot access your local variables since they are gone, unless you mark them as final

Upvotes: 17

abson
abson

Reputation: 9348

Your inner class is final and so you shouldn't be able to modify anything from inside your final entity.

Upvotes: 1

ControlAltDel
ControlAltDel

Reputation: 35011

The answer is the two are in different scopes. So that variable could change before the inner class accesses it. Making it final prevents that.

Upvotes: 13

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