Reputation: 509
Hi I am having trouble encoding a 1000 symbol message with Extended Huffman coding. I have the dictionary already. I just need to encode the message. However, I am not sure how to do this. Any ideas?
I am using Matlab bdw.
Upvotes: 1
Views: 2413
Reputation: 509
Here is the code I used:
%Extended Huffman
prob=0.1;
m=4;
%Generating the probabilities
for i = 1:2^m
q(i) = 1;
for j=0: m-1
b=2^j;
if bitand(i-1,b)
q(i)= q(i)*prob;
else
q(i)= q(i)*(1-prob);
end
end
end
disp ('Sum of probabilities');
disp (sum(q));
disp('Entropy per symbol');%should be equal to 1
E=sum(q.*log2(1./q));
disp(E/m);
%huffman
s=0:2^m-1; %There are 16 symbols from 0000 -> 1111
[dict,avglen] = huffmandict(s,q); %probabilities
I have tried this approach for extended Huffman and the message size did decrease but not by a lot and I don't know if it is a correct approach. The message was first divided into 4 bits and the decimal value obtained was compared to the dictionary. The new encoded message was then obtained:
for j=(0:4:1000-1)
newcode=message(j+1:j+4); %Dividing the message into 4 bits and saving the
%corresponding decimal values
array(:,a)=bi2de(newcode);
a=a+1;
end
for(f=1:250)
for(i=1:15)
if(array(f)==cell2mat((dict(i,1)))) %cell2mat will obtain the value of the cell
encodedmsg= horzcat(encodedmsg, dict(i,2)); %horzcat will concatenate the array with its corresponding codeword
end
end
end
Upvotes: 2