CODEWITHSUNDEEP
c#
jaggi
jaggi

Reputation: 59

How are methods invoked using Reflection

I want to know that how the methods are invoked using Reflection in c# .

Here is the code i have picked from book

using System;
using System.Reflection;
class MyClass {
int x;
int y;
public MyClass(int i, int j) {
x = i;
y = j;
}
public int Sum() {
return x+y;
}
public bool IsBetween(int i) {
if((x < i) && (i < y)) return true;
else return false;
}
public void Set(int a, int b) {
Console.Write("Inside Set(int, int). ");
x = a;
      y = b;
Show();
}
// Overload set.
public void Set(double a, double b) {
Console.Write("Inside Set(double, double). ");
x = (int) a;
y = (int) b;
Show();
}
public void Show() {
Console.WriteLine("Values are x: {0}, y: {1}", x, y);
}
public void Show1() {
Console.WriteLine("Hello");
} 
}
class InvokeMethDemo {
static void Main() {
Type t = typeof(MyClass);
MyClass reflectOb = new MyClass(10, 20);
int val;
Console.WriteLine("Invoking methods in " + t.Name);
Console.WriteLine();
MethodInfo[] mi = t.GetMethods();
// Invoke each method.
foreach(MethodInfo m in mi) {
// Get the parameters.
ParameterInfo[] pi = m.GetParameters();
if(m.Name.Equals("Set", StringComparison.Ordinal) &&
pi[0].ParameterType == typeof(int)) {
object[] args = new object[2];
args[0] = 9;
args[1] = 18;
m.Invoke(reflectOb, args);
}
else if(m.Name.Equals("Set", StringComparison.Ordinal) &&
pi[0].ParameterType == typeof(double)) {
object[] args = new object[2];
args[0] = 1.12;
args[1] = 23.4;
m.Invoke(reflectOb, args);
}
else if(m.Name.Equals("Sum", StringComparison.Ordinal)) {
val = (int) m.Invoke(reflectOb, null);
Console.WriteLine("sum is " + val);
}
else if(m.Name.Equals("IsBetween", StringComparison.Ordinal)) {
object[] args = new object[1];
args[0] = 14;
if((bool) m.Invoke(reflectOb, args))
Console.WriteLine("14 is between x and y");
}
else if(m.Name.Equals("Show", StringComparison.Ordinal)) {
m.Invoke(reflectOb, null);

}
else if(m.Name.Equals("Show1", StringComparison.Ordinal)) {
m.Invoke(reflectOb, null);
}         
}
}
}
  1. Is the method invoked based on the number and type of parameters passed.If yes then Why

the Compiler does not show error as the **same statement is used to call method show and

show1**?

OR

  1. The method is invoked based on some reference value of m(MethodInfo m) and the number of parameters.

Upvotes: 1

Views: 185

Answers (1)

Hemant Kumar
Hemant Kumar

Reputation: 4611

You can invoke the Methods using MethodBase Class.

Invokes the method or constructor represented by the current instance, using the specified parameters. Refer this link Method Invoking in Reflection

Upvotes: 1

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