CODEWITHSUNDEEP
xmlxslt
Vlad Z.
Vlad Z.

Reputation: 3451

Format XML file

I have following xml file:

        <table name="countries">
            <column name="id">1</column>
            <column name="name">Abkhazia</column>
            <column name="code">XZ</column>
            <column name="phone_code">+995</column>
            <column name="flag">xz.gif</column>
        </table>

how can i format this xml to something like this? 

        <countries>
            <id>1</id>
            <name>Abkhazia</name>
            <code>XZ</code>
            <phone_code>+995</phone_code>
            <flag>xz.gif</flag>
        </countries>

is there some online resources for this?

Upvotes: 0

Views: 158

Answers (2)

Dimitre Novatchev
Dimitre Novatchev

Reputation: 243599

This short and simple transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="*">
  <xsl:element name="{@name}">
    <xsl:apply-templates/>
  </xsl:element>
 </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<table name="countries">
    <column name="id">1</column>
    <column name="name">Abkhazia</column>
    <column name="code">XZ</column>
    <column name="phone_code">+995</column>
    <column name="flag">xz.gif</column>
</table>

produces the wanted, correct result:

<countries>
   <id>1</id>
   <name>Abkhazia</name>
   <code>XZ</code>
   <phone_code>+995</phone_code>
   <flag>xz.gif</flag>
</countries>

Upvotes: 2

pointer
pointer

Reputation: 579

It is just basic work with xml in any programming language. I've done it in XSLT without programming, transformation which produces desired output (tested here: XSLT Transformation - Online Toolz), mabye there is more elegant way, I'm not expert in XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="utf-8" indent="no"/>

<xsl:template match="table">
<xsl:variable name="tableName" select="@name"></xsl:variable>
<xsl:element name="{$tableName}">
  <xsl:for-each select="column">
     <xsl:variable name="columnName" select="@name"></xsl:variable>
     <xsl:element name="{$columnName}">
     <xsl:value-of select="."/> 
   </xsl:element>
  </xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

Upvotes: 3

Related Questions