Reputation: 98
I've tried a lot of things, but nothing is working.
When I click on an mage, I want it's z-index to be "9999". When I click to show another image, I want the previous image's z-index to go back to "0".
So basically, I only want one image to show at a time - I want a specific function to run for each image.
http://jsfiddle.net/WarrenBee/a78R7/
PLEASE help me!
Upvotes: 1
Views: 1091
Reputation: 1074809
Just remember the last image and value and put the old value back:
var lastImage, lastZIndex;
$('.char').click(function () {
var thisImage = $(this).children('img');
if (lastImage) {
lastImage.css('z-index', lastZIndex);
}
lastImage = thisImage;
lastZIndex = thisImage.css('z-index');
thisImage.css({'z-index' : '9999'})
});
Ideally, avoid creating global variables by wrapping all of that in a function:
(function() {
var lastImage, lastZIndex;
$('.char').click(function () {
var thisImage = $(this).children('img');
if (lastImage) {
lastImage.css('z-index', lastZIndex);
}
lastImage = thisImage;
lastZIndex = thisImage.css('z-index');
thisImage.css({'z-index' : '9999'})
});
})();
Upvotes: 0
Reputation: 12753
Change your JavaScript to this:
$('.char').click(function () {
$('.char img').css({'z-index' : '0'});
$(this).children('img').css({'z-index' : '9999'});
});
This will set the z-index of all imgs inside a char class back to 0, before setting the one that was clicked to 9999.
Upvotes: 1