CODEWITHSUNDEEP
phploopsswitch-statementinfinite
William Boman
William Boman

Reputation: 2227

Infinite loop - why?

for($i=0; $i<5; $i++) {
    switch($i) {
        case 0:
            echo "<div class=\"darkgrey topdarkgrey\">";
            break;
        case 1:
        case 3:
            echo "<div class=\"lightgrey\">";
            break;
        case 2:
        case 4:
            echo "<div class=\"darkgrey\">";
            break;
        case 5:
            echo "<div class\"darkgrey bottomdarkgrey\">";
            break;
    }
    if($i=$idagInt) 
        echo "<div id=\"idag\">" . $dag[$i] . "<br>";
    else
        echo "<div class=\"dag\"><span class=\"veckoDag\">" . $dag[$i] . "</span><br>";

    echo "<span class=\"month\">" . $datumDay[$i] . " " . $month[$i] . "</span></div>";
    echo "<div class=\"mat\">" . strip_tags($mat[$i], "<p>") . "</div></div>";
}

This is the code I'm using to print things to the website and after some trouble-shooting my conclusion is that there's something wrong with the switch-statement, but I cant see what?

Upvotes: 0

Views: 112

Answers (1)

John Conde
John Conde

Reputation: 219834

Here's your problem. You're assigning $i the value of $idagInt rather then comparing it. As a result $i never reaches 5.

if($i=$idagInt)

Change it to:

if($i==$idagInt)

Upvotes: 7

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