CODEWITHSUNDEEP
phpmath
user127886
user127886

Reputation: 317

PHP math (numbering)

$temp is currently 6. But the variable result can be changing every time to a different number so it is not a fixed value.

Anyway, for this $temp * 1.1666666, the result will be 6.99999996. Since I used the floor function, it will be rounded down to 6.

Is there any way when the value is more then>*.49999 it will stay at *.5 instead of *?

Example: 6.51111111, 6.78948123, 6.9747124

Expected Output: 6.5

Example: 6.49999999, 6.12412431, 6.33452361

Expected Output: 6

Do note that, $temp value will be ever changing..thank you!

Upvotes: 1

Views: 136

Answers (2)

Ashwini Agarwal
Ashwini Agarwal

Reputation: 4858

Try this code...

<?php 

    $temp = 6.94444;
    echo myRound($temp);

   function myRound($temp)
    {
        $frac = $temp - floor($temp);
        $frac = ($frac >= .5) ? .5 : 0;
        return ( floor($temp) + $frac );
    }

?>

Hope this is what you want.

Upvotes: 0

John Conde
John Conde

Reputation: 219834

Use round($number, 1). That will round to the nearest decimal point.

$number = round(.1666666 * $temp, 1);

If you want to round to the nearest half you can do this:

function round_to_half($num)
{
  if($num >= ($half = ($ceil = ceil($num))- 0.5) + 0.25) return $ceil;
  else if($num < $half - 0.25) return floor($num);
  else return $half;
}

$number = round_to_half(.1666666 * $temp);

Upvotes: 5

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