j5shi
j5shi

Reputation: 867

How to get all sub-elements of an element tree with Python ElementTree?

I want to find a way to get all the sub-elements of an element tree like the way ElementTree.getchildren() does, since getchildren() is deprecated since Python version 2.7.
I don't want to use it anymore, though I can still use it currently.

Upvotes: 42

Views: 142315

Answers (5)

Eypros
Eypros

Reputation: 5723

Maybe this does not correspond to OP actual question but in a greater sense I would suggest that if someone want to get all elements named with a certain name e.g. 'object' can use (an alternative approach to @Turtles Are Cute which to me at least seems more natural):

objs = tree.findall('object')

which also returns a list.

Upvotes: 3

Harshal Zope
Harshal Zope

Reputation: 1576

in the pydoc it is mentioned to use list() method over the node to get child elements.
list(elem)

Upvotes: 19

Turtles Are Cute
Turtles Are Cute

Reputation: 3426

None of the existing answers will find all children. This solution uses BeautifulSoup instead of ETree, but will find all children, instead of just top-level:

from bs4 import BeautifulSoup    

with open(filename) as f:
    soup = BeautifulSoup(f, 'xml')

results = soup.find_all('element_name')

Upvotes: 3

pepr
pepr

Reputation: 20744

If you want to get all elements 'a', you can use:

a_lst = list(elem.iter('a'))

If the elem is also 'a', it will be included.

Upvotes: 8

Eli Bendersky
Eli Bendersky

Reputation: 273366

All sub-elements (descendants) of elem:

all_descendants = list(elem.iter())

A more complete example:

>>> import xml.etree.ElementTree as ET
>>> a = ET.Element('a')
>>> b = ET.SubElement(a, 'b')
>>> c = ET.SubElement(a, 'c')
>>> d = ET.SubElement(a, 'd')
>>> e = ET.SubElement(b, 'e')
>>> f = ET.SubElement(d, 'f')
>>> g = ET.SubElement(d, 'g')
>>> [elem.tag for elem in a.iter()]
['a', 'b', 'e', 'c', 'd', 'f', 'g']

To exclude the root itself:

>>> [elem.tag for elem in a.iter() if elem is not a]
['b', 'e', 'c', 'd', 'f', 'g']

Upvotes: 29

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