Reputation: 751
I'm writing a logging class at the moment. The Logger works with streams and also prints the object which is logging at the moment. Here is the macro:
#define OBJLOG(DL, what) DL <= this->Logger->getDebugLevel() ? *this->Logger << DL << "[" << this->Name << "]: "<< what << std::endl : this->Logger->doNothing();
The pseudo code Variant for better overview:
#define OBJLOG(debuglevel, what) debuglevel <= logger.debuglevel ? logger.log(what) : logger.doNothing()
Is there any way to get around the doNothing function call, like doing nothing at all?
Upvotes: 3
Views: 636
Reputation: 3074
#define OBJLOG(DL, what) do { if(DL <= this->Logger->getDebugLevel()) *this->Logger << DL << "[" << this->Name << "]: "<< what << std::endl; } while(0)
See Why use apparently meaningless do-while and if-else statements in macros? for an explanation. (The do {} while(0)
isn't strictly necessary here, but I would prefer not to leak an ostream
.)
Also, you should always wrap macro argument uses in parentheses, like:
#define OBJLOG(DL, what) do { if((DL) <= this->Logger->getDebugLevel()) *this->Logger << (DL) << "[" << this->Name << "]: "<< (what) << std::endl; } while(0)
Finally, you should move this code into a function and call that in your macro (if you really insist on using a macro) to avoid evaluating your macro arguments more than once.
Upvotes: 4
Reputation: 4770
Have your logger.log() function return a boolean.
Connect your predicates with an and like this: debuglevel <= logger.debuglevel && logger.log
That should do the trick.
Upvotes: 1