CODEWITHSUNDEEP
phpheadergravatar
user1260310
user1260310

Reputation: 2227

php check if gravatar exists header error

I'm trying to check if a gravatar exists. When I try the approach recommended in earlier questions, I get an error " Warning: get_headers() [function.get-headers]: This function may only be used against URLs" Anyone seen this or see the error in my code? PS I do not want to specify a default image for gravatar to serve as there could be more than one default possibilities if no gravatar exits.

Also, I found a reference to error possibly being related to my ini file which I don't think my host gives me access to. If so, is there an alternative to getheaders? Many thanks.

$email = $_SESSION['email'];
$email= "[email protected]"; //for testing
$gravemail = md5( strtolower( trim( $email ) ) );
$gravsrc = "http://www.gravatar.com/avatar/".$gravemail;
$gravcheck = "http://www.gravatar.com/avatar/".$gravemail."?d=404";
$response = get_headers('$gravcheck');
echo $response;
exit;
if ($response != "404 Not Found"..or whatever based on response above){
$img = $gravsrc;
}

Upvotes: 4

Views: 2831

Answers (2)

Maniruzzaman Akash
Maniruzzaman Akash

Reputation: 5025

While doing my one of a project, I had made a simple function of Gravatar in php.

You can see it.

  <?php

  class GravatarHelper
  {

    /**
    * validate_gravatar
    *
    * Check if the email has any gravatar image or not
    *
    * @param  string $email Email of the User
    * @return boolean true, if there is an image. false otherwise
    */
    public static function validate_gravatar($email) {
      $hash = md5($email);
      $uri = 'http://www.gravatar.com/avatar/' . $hash . '?d=404';
      $headers = @get_headers($uri);
      if (!preg_match("|200|", $headers[0])) {
        $has_valid_avatar = FALSE;
      } else {
        $has_valid_avatar = TRUE;
      }
      return $has_valid_avatar;
    }



    /**
    * gravatar_image
    *
    *  Get the Gravatar Image From An Email address
    *
    * @param  string $email User Email
    * @param  integer $size  size of image
    * @param  string $d     type of image if not gravatar image
    * @return string        gravatar image URL
    */
    public static function gravatar_image($email, $size=0, $d="") {
      $hash = md5($email);
      $image_url = 'http://www.gravatar.com/avatar/' . $hash. '?s='.$size.'&d='.$d;
      return $image_url;
    }

  }

In here, there are two functions.

  1. validate_gravatar() will return true or false based on if the email has any gravatar or not.
  2. gravatar_image() will return the gravatar image url for your email

Hope it will help to others.

Upvotes: 0

Baba
Baba

Reputation: 95103

Observation

A. get_headers('$gravcheck'); would not work because of use of single quote '

B. calling exit; would terminate script prematurely

C. $response would return an array you can not use echo to print the information use print_r insted

D. $response != "404 Not Found" would not work because $response is array

This is the proper way to do it :

$email= "[email protected]"; //for testing
$gravemail = md5( strtolower( trim( $email ) ) );
$gravsrc = "http://www.gravatar.com/avatar/".$gravemail;
$gravcheck = "http://www.gravatar.com/avatar/".$gravemail."?d=404";
$response = get_headers($gravcheck);
print_r($response);
if ($response[0] != "HTTP/1.0 404 Not Found"){
    $img = $gravsrc;
}

Upvotes: 12

Related Questions