CODEWITHSUNDEEP
pythonhtmldjangowebrender-to-response
Treper
Treper

Reputation: 3653

Why the render_to_response not working properly

This is a snippet of my code. 

soup=BeautifulSoup(html_document)
tabulka=soup.find("table",width="100%")
dls=tabulka.findAll("dl",{"class":"resultClassify"})
tps=tabulka.findAll("div",{"class":"pageT clearfix"})
return render_to_response('result.html',{'search_key':search_key,'turnpages
':tps,'bookmarks':dls})

I checked the dls, it is a dict contains only one html label 

<dl>label contents contains some <dd> labels</dl>

But after pass dls to render_to_response the result is not correct. The corresponding template code in result.html is:

{% if bookmarks %}
{% for bookmark in bookmarks %}
{{bookmark|safe}}
{% endfor %}
{% else %}
<p>No bookmarks found.</p>
{% endif %}

The output result html contains a python dictionary format like this:

[<dd>some html</dd>,<dd>some html</dd>,<dd>some html</dd>,...]

This appears in the output html. That is very strange. Is this a bug of renfer_to_response?

Upvotes: 1

Views: 797

Answers (2)

Anshuma
Anshuma

Reputation: 3472

You have to use a RequestContext instance when rendering templates in Django.

say like this

return render_to_response('login.html',{'at':at}, context_instance = RequestContext(request))

for this to use, you need to import as follows:

from django.template import RequestContext

Hope this works for you. :)

Upvotes: 1

Zarkonnen
Zarkonnen

Reputation: 22478

Well, dls is a python list containing the text of all the matching elements. render_to_response doesn't know what to do with a list, so it just turns it into a string. If you want to insert all the elements as HTML, try joining them into a single piece of text like so:

dls = "".join(dls)

Note that by doing so you are pasting live HTML from some other source into your own page, which is potentially unsafe. (What happens if one of the dds contains malicious Javascript? Do you trust the provider of that HTML?)

Upvotes: 2

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