CODEWITHSUNDEEP
phpmysql
Richard
Richard

Reputation:

how to write this sql statement

I have a rather simple question. How would I write this statement in php?

$q="SELECT t1.gebruikersnaam FROM tbel_leden as t1,instellingen as t2 WHERE
    t2.ledenid=t1.ledenid AND t2.livetracking=1";

I know it's just supposed to be a string but the error says unexpected t_variable and php admin is not helping either.

Thanks

Upvotes: 1

Views: 181

Answers (2)

vaske
vaske

Reputation: 9542

$q="SELECT t1.gebruikersnaam FROM tbel_leden as t1 Left join instellingen as t2 on t2.ledenid=t1.ledenid WHERE t2.livetracking=1";

or

$q="SELECT t1.gebruikersnaam FROM tbel_leden as t1 join instellingen as t2 on t2.ledenid=t1.ledenid WHERE t2.livetracking=1";

it depends on what you want to get from DB. It's recommended to read a SQL spec about JOIN.

<?php
$con = mysql_connect("localhost","username","password");
if (!$con){
  die('We don't have a connection: ' . mysql_error());
}

mysql_select_db("yourDB", $con);


$q = "SELECT t1.gebruikersnaam FROM tbel_leden as t1 Left join instellingen as t2 on       t2.ledenid=t1.ledenid WHERE t2.livetracking=1"; 
$result = mysql_query($q); 

while ($row = mysql_fetch_array($result,MYSQL_NUM)){ 
echo $row[0]."<br />"; 
} 


?>

you should try this code snippet.

Upvotes: 0

Quassnoi
Quassnoi

Reputation: 425291

Missed a dollar sign to denote a php variable:

$q="SELECT t1.gebruikersnaam FROM tbel_leden as t1,instellingen as t2 WHERE t2.ledenid=t1.ledenid AND t2.livetracking=1";

Upvotes: 3

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