CODEWITHSUNDEEP
pythonlistdictionary
user1335606
user1335606

Reputation: 503

How do I convert a list of strings to a dictionary?

My list is something like this,

['"third:4"', '"first:7"', '"second:8"']

I want to convert this into a dictionary like this...

{"third": 4, "first": 7, "second": 8}

How do I do this in Python?

Upvotes: 0

Views: 194

Answers (4)

Kracekumar
Kracekumar

Reputation: 20419

With map and dict it is very straight forward.

syntax for map

map(func, iterables)

to_dict will return key, value which will be consumed by dict

def to_dict(item):  
      return item[0].replace('"',''), int(item[1].replace('"', ''))

>>> items
6: ['"third:4"', '"first:7"', '"second:8"']
>>> dict(map(to_dict, [item.split(':') for item in items]))
7: {'first': 7, 'second': 8, 'third': 4}

help(dict)

class dict(object)   
     dict() -> new empty dictionary
     dict(mapping) -> new dictionary initialized from a mapping object's
     (key, value) pairs

     dict(iterable) -> new dictionary initialized as if via:
     d = {}
     for k, v in iterable:
         d[k] = v
    dict(**kwargs) -> new dictionary initialized with the name=value pairs
       in the keyword argument list.  For example:  dict(one=1, two=2)

Final Code

>>> dict(map(to_dict, [item.split(':') for item in items]))

Upvotes: 0

hakunami
hakunami

Reputation: 2441

def listToDic(lis):
    dic = {}
    for item in lis:
        temp = item.strip('"').split(':')
        dic[temp[0]] = int(temp[1])
    return dic

Upvotes: 1

jamylak
jamylak

Reputation: 133534

>>> data
['"third:4"', '"first:7"', '"second:8"']
>>> dict((k,int(v)) for k,v in (el.strip('\'"').split(':') for el in data))
{'second': 8, 'third': 4, 'first': 7}

or

>>> data = ['"third:4"', '"first:7"', '"second:8"']
>>> def convert(d):
        for el in d:
            key, num = el.strip('\'"').split(':')
            yield key, int(num)


>>> dict(convert(data))
{'second': 8, 'third': 4, 'first': 7}

Upvotes: 3

ThiefMaster
ThiefMaster

Reputation: 318488

Here are two possible solutions, one that gives you string values and one that gives you int values:

>>> lst = ['"third:4"', '"first:7"', '"second:8"']
>>> dict(x[1:-1].split(':', 1) for x in lst)
{'second': '8', 'third': '4', 'first': '7'}
>>> dict((y[0], int(y[1])) for y in (x[1:-1].split(':', 1) for x in lst))
{'second': 8, 'third': 4, 'first': 7}

However, for the sake of readability, you could split the conversion into two steps:

>>> lst = ['"third:4"', '"first:7"', '"second:8"']
>>> dct = dict(x[1:-1].split(':', 1) for x in lst)
>>> {k: int(v) for k, v in dct.iteritems()}

Of course this has some overhead since you create a dict twice - but for a small list it doesn't matter.

Upvotes: 6

Related Questions