CODEWITHSUNDEEP
php
Gunnit
Gunnit

Reputation: 1074

How to hide dynamic content with php?

i was wandering how i could hide content of a page based on the page you are located , i did this with the code from below , however i was wondering how i could hide a page that is generated dynamically for example index.php*?id=......*.

Is there a php function that i could use that would say disregard all that is after .php so don't take into consideration ?id=.. . 

if($_SERVER['PHP_SELF'] != "/3uboats/index.php"){

CONTENT TO HIDE 

}

If i was not clear plz ask for clarification , thanks all in advance

i want to hide content for this page stampa_fattura_partenza.php?id_prenotazione_partenze=1 the 1 is generated by php , its dynamic

Upvotes: 0

Views: 685

Answers (3)

Hans Wassink
Hans Wassink

Reputation: 2577

What you can do is get the value of your id using $_REQUEST["id_prenotazione_partenze"] or $_GET["id_prenotazione_partenze"] and use that in your php IF.

if($_REQUEST["id_prenotazione_partenze"]==1){
    // HIDE
}

This hides content when your page id = 1 for example.

Upvotes: 1

Michael Sazonov
Michael Sazonov

Reputation: 1533

You can check whether $_REQUEST[ "id_prenotazione_partenze" ] is set, like:

if( isset( $_REQUEST[ "id_prenotazione_partenze" ] ) ){
//hide content
}

Then if any value is passed with $_REQUEST[ "id_prenotazione_partenze" ] it will evaluate the if statement.

Upvotes: 1

rekire
rekire

Reputation: 47945

You should better not use $_SERVER['PHP_SELF'] that is insecure. You could check if a variable is set by this code:

if(isset($_GET['id_prenotazione_partenze']) &&
         $_GET['id_prenotazione_partenze'] != 1) {
    ...
}

This should work for your example.

Upvotes: 1

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