Reputation: 13
I have a serious issue with QtPlugin. I try to build a plugin from an interface, named dictionary:
class dictionary
{
private:
... some private members
public:
~dictionary();
... some no virtual methods
virtual void collectData()=0;
virtual void collectOperator()=0;
virtual void collectControl()=0;
};
QT_BEGIN_NAMESPACE
Q_DECLARE_INTERFACE(CDictionnary, "shinoe.cameleon.dictionary/2.0")
QT_END_NAMESPACE
I have implemented dictionary in a blankdictionary class declared like this (blankdictionary.h) in a blankdictionary project.
The .pro file:
!include(../../../configuration.pri)
QT += core gui
TARGET = blanktarget
TEMPLATE = lib
CONFIG += plugin
#dictionary interface includes
!include(../../../machine/kernel/includekernel.pri)
SOURCES += blankdictionary.cpp
HEADERS += blankdictionary.h
The blankdictionary.h file:
class blankdictionary : public dictionary {
Q_OBJECT
Q_INTERFACES(dictionary)
public:
blankdictionary();
void collectData();
void collectOperator();
void collectControl();
};
At the end of my blankdictionary.cpp file I have:
QT_BEGIN_NAMESPACE
Q_EXPORT_PLUGIN2(blanktarget, blankdictionary)
QT_END_NAMESPACE
At compile, it returns this error:
blankdictionary.cpp: In function 'QObject* qt_plugin_instance()':
blankdictionary.cpp:20: error: no match for 'operator=' in '_instance = (operator new(44u), (<statement>, ((blankdictionary*)<anonymous>)))'
c:\QtSDK\Desktop\Qt\4.7.4\mingw\include/QtCore/qpointer.h:65: note: candidates are: QPointer<T>& QPointer<T>::operator=(const QPointer<T>&) [with T = QObject]
c:\QtSDK\Desktop\Qt\4.7.4\mingw\include/QtCore/qpointer.h:67: note: QPointer<T>& QPointer<T>::operator=(T*) [with T = QObject]
any idea?
Thanks in advance !
Upvotes: 1
Views: 426
Reputation: 22346
Another problem (as well as the one you have mentioned in your comment), is that you have declared the Q_OBJECT
macro in the blankdictionary
class, but then not derived it from QObject
.
Upvotes: 2