CODEWITHSUNDEEP
sqlsql-servert-sql
Byron Whitlock
Byron Whitlock

Reputation: 53851

Get the last day of the month in SQL

I need to get the last day of the month given as a date in SQL. If I have the first day of the month, I can do something like this:

DATEADD(DAY, DATEADD(MONTH,'2009-05-01',1), -1)

But does anyone know how to generalize it so I can find the last day of the month for any given date?

Upvotes: 73

Views: 332699

Answers (23)

Nilton
Nilton

Reputation: 27

user a function EOMONTH(GETDATE())

SELECT EOMONTH(GETDATE())

Upvotes: -1

LukeH
LukeH

Reputation: 269308

Here's my version. No string manipulation or casting required, just one call each to the DATEADD, YEAR and MONTH functions:

DECLARE @test DATETIME
SET @test = GETDATE()  -- or any other date

SELECT DATEADD(month, ((YEAR(@test) - 1900) * 12) + MONTH(@test), -1)

This works by taking the number of months that have passed since the initial date in SQL's date system (1/1/1990), then adding that number of months to the date "-1" (12/31/1899) using the DATEADD function, which returns a proper datetime at the corresponding month's end (that of the date you specified). It relies on the fact that December always ends on the 31st and there are no months longer than that.

Upvotes: 75

ianhollo
ianhollo

Reputation: 9

--## Useful Date Functions

SELECT

GETDATE() AS [DateTime],

CAST(GETDATE() AS DATE) AS [Date],

DAY(GETDATE()) AS [Day of Month],

FORMAT(GETDATE(),'MMMM') AS [Month Name],

FORMAT(GETDATE(),'MMM') AS [Month Short Name],

FORMAT(GETDATE(),'MM') AS [Month No],

YEAR(GETDATE()) AS [Year],

CAST(DATEADD(DD,-(DAY(GETDATE())-1),GETDATE()) AS DATE) AS [Month Start Date],

EOMONTH(GETDATE()) AS [Month End Date],

CAST(DATEADD(M,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Previous Month Start Date],

CAST(DATEADD(S,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Previous Month End Date],

CAST(DATEADD(M,+1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Next Month Start Date],

CAST(DATEADD(D,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE())+2,0)) AS DATE) AS [Next Month End Date],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE()),0) AS DATE) AS [First Day of Current Week],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+1,-1) AS DATE) AS [Last Day of Current Week],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())-1,0) AS DATE) AS [First Day of Last Week],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE()),-1) AS DATE) AS [Last Day of Last Week],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+1,0) AS DATE) AS [First Day of Next Week],

CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+2,-1) AS DATE) AS [Last Day of Next Week]

Upvotes: 0

shieldgenerator7
shieldgenerator7

Reputation: 1736

I couldn't find an answer that worked in regular SQL, so I brute forced an answer:

SELECT *
FROM orders o
WHERE (MONTH(o.OrderDate) IN ('01','03','05','07','08','10','12') AND DAY(o.OrderDate) = '31')
    OR (MONTH(o.OrderDate) IN ('04','06','09','11') AND DAY(o.OrderDate) = '30')
    OR (MONTH(o.OrderDate) IN ('02') AND DAY(o.OrderDate) = '28')

Upvotes: 0

Satinder singh
Satinder singh

Reputation: 10198

For SQL server 2012 or above use EOMONTH to get the last date of month

SQL query to display end date of current month

DECLARE @currentDate DATE = GETDATE()
SELECT EOMONTH (@currentDate) AS CurrentMonthED

SQL query to display end date of Next month

DECLARE @currentDate DATE = GETDATE()
SELECT EOMONTH (@currentDate, 1 ) AS NextMonthED

Upvotes: 5

Siluxmedia
Siluxmedia

Reputation: 27

Based on the most voted answer at below link I came up with the following solution:

 declare  @mydate date= '2020-11-09';
  SELECT DATEADD(month, DATEDIFF(month, 0, @mydate)+1, -1) AS lastOfMonth

link: How can I select the first day of a month in SQL?

Upvotes: 0

radouans
radouans

Reputation: 9

---Start/End of previous Month 
Declare @StartDate datetime, @EndDate datetime

set @StartDate = DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0) 
set @EndDate = EOMONTH (DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0)) 

SELECT @StartDate,@EndDate

Upvotes: -2

Serkan Arslan
Serkan Arslan

Reputation: 13393

This query can also be used.

DECLARE @SelectedDate DATE =  GETDATE()

SELECT DATEADD(DAY, - DAY(@SelectedDate), DATEADD(MONTH, 1 , @SelectedDate)) EndOfMonth

Upvotes: 1

Sri
Sri

Reputation: 155

Works in SQL server

Declare @GivenDate datetime
SET @GivenDate = GETDATE()

Select DATEADD(MM,DATEDIFF(MM, 0, @GivenDate),0) --First day of the month 

Select DATEADD(MM,DATEDIFF(MM, -1, @GivenDate),-1) --Last day of the month

Upvotes: 6

Martin Smith
Martin Smith

Reputation: 452988

From SQL Server 2012 you can use the EOMONTH function.

Returns the last day of the month that contains the specified date, with an optional offset.

Syntax

EOMONTH ( start_date [, month_to_add ] )

How ... I can find the last day of the month for any given date?

SELECT EOMONTH(@SomeGivenDate)

Upvotes: 105

Başar Kaya
Başar Kaya

Reputation: 364

I wrote following function, it works.

It returns datetime data type. Zero hour, minute, second, miliseconds. 

CREATE Function [dbo].[fn_GetLastDate]
(
    @date datetime
)
returns datetime
as
begin

declare @result datetime

 select @result = CHOOSE(month(@date),  
 DATEADD(DAY, 31 -day(@date), @date),
 IIF(YEAR(@date) % 4 = 0, DATEADD(DAY, 29 -day(@date), @date), DATEADD(DAY, 28 -day(@date), @date)), 
 DATEADD(DAY, 31 -day(@date), @date) ,
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date),
 DATEADD(DAY, 31 -day(@date), @date),
 DATEADD(DAY, 30 -day(@date), @date), 
 DATEADD(DAY, 31 -day(@date), @date))

 return convert(date, @result)

end

It's very easy to use. 2 example:

select [dbo].[fn_GetLastDate]('2016-02-03 12:34:12')

select [dbo].[fn_GetLastDate](GETDATE())

Upvotes: 0

David
David

Reputation: 21

WinSQL: I wanted to return all records for last month:

where DATE01 between dateadd(month,-1,dateadd(day,1,dateadd(day,-day(today()),today()))) and dateadd(day,-day(today()),today())

This does the same thing:

where month(DATE01) = month(dateadd(month,-1,today())) and year(DATE01) = year(dateadd(month,-1,today()))

Upvotes: 1

LONG
LONG

Reputation: 4610

Try to run the following query, it will give you everything you want :)

Declare @a date =dateadd(mm, Datediff(mm,0,getdate()),0)
Print('First day of Current Month:')
Print(@a)
Print('')
set @a = dateadd(mm, Datediff(mm,0,getdate())+1,-1)
Print('Last day of Current Month:')
Print(@a)
Print('')

Print('First day of Last Month:')
set @a = dateadd(mm, Datediff(mm,0,getdate())-1,0)
Print(@a)
Print('')

Print('Last day of Last Month:') 
set @a = dateadd(mm, Datediff(mm,0,getdate()),-1)
Print(@a)
Print('')


Print('First day of Current Week:')
set @a = dateadd(ww, Datediff(ww,0,getdate()),0)
Print(@a)
Print('')

Print('Last day of Current Week:')
set @a = dateadd(ww, Datediff(ww,0,getdate())+1,-1)
Print(@a)
Print('')

Print('First day of Last Week:')
set @a =  dateadd(ww, Datediff(ww,0,getdate())-1,0)
Print(@a)
Print('')

Print('Last day of Last Week:')
set @a =  dateadd(ww, Datediff(ww,0,getdate()),-1)
Print(@a)

Upvotes: 1

David
David

Reputation: 21

WinSQL to get last day of last month (i.e today is 2017-02-09, returns 2017-01-31: Select dateadd(day,-day(today()),today())

Upvotes: 1

Trilok
Trilok

Reputation: 9

Using SQL Server, here is another way to find last day of month : 

SELECT DATEADD(MONTH,1,GETDATE())- day(DATEADD(MONTH,1,GETDATE()))

Upvotes: 0

Stu
Stu

Reputation: 31

Based on the statements: 

SELECT DATEADD(MONTH, 1, @x)           -- Add a month to the supplied date @x

and

SELECT DATEADD(DAY,  0 - DAY(@x), @x)  -- Get last day of month previous to the supplied date @x

how about adding a month to date @x and then retrieving the last day of the month previous to that (i.e. The last day of the month of the supplied date)

DECLARE @x  DATE = '20-Feb-2012' 
SELECT DAY(DATEADD(DAY,  0 - DAY(DATEADD(MONTH, 1, @x)), DATEADD(MONTH, 1, @x)))

Note: This was test using SQL Server 2008 R2

Upvotes: 3

peter.petrov
peter.petrov

Reputation: 39437

Take some base date which is the 31st of some month e.g. '20011231'. Then use the
following procedure (I have given 3 identical examples below, only the @dt value differs).

declare @dt datetime;

set @dt = '20140312'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');



set @dt = '20140208'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');



set @dt = '20140405'

SELECT DATEADD(month, DATEDIFF(month, '20011231', @dt), '20011231');

Upvotes: 0

Aulia
Aulia

Reputation: 11

This works for me, using Microsoft SQL Server 2005:

DATEADD(d,-1,DATEADD(mm, DATEDIFF(m,0,'2009-05-01')+1,0))

Upvotes: 1

Goca
Goca

Reputation: 1873

I know this is a old question but here is another solution that works for me 

SET @dtDate = "your date"
DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@dtDate)+1,0))

And if some one is looking for different examples here is a link http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/

I hope this helps some one else. stackoverflow Rocks!!!!

Upvotes: 4

Peter Perháč
Peter Perháč

Reputation: 20782

using sql server 2005, this works for me:

select dateadd(dd,-1,dateadd(mm,datediff(mm,0,YOUR_DATE)+1,0))

Basically, you get the number of months from the beginning of (SQL Server) time for YOUR_DATE. Then add one to it to get the sequence number of the next month. Then you add this number of months to 0 to get a date that is the first day of the next month. From this you then subtract a day to get to the last day of YOUR_DATE.

Upvotes: 0

jamuraa
jamuraa

Reputation: 3419

You could get the days in the date by using the DAY() function: 

dateadd(day, -1, dateadd(month, 1, dateadd(day, 1 - day(date), date)))

Upvotes: 14

Raj
Raj

Reputation: 10843

My 2 cents:

select DATEADD(DAY,-1,DATEADD(MONTH,1,DATEADD(day,(0-(DATEPART(dd,'2008-02-12')-1)),'2008-02-12')))

Raj

Upvotes: 0

Eric
Eric

Reputation: 95113

Just extend your formula out a little bit:

dateadd(day, -1,
    dateadd(month, 1,
        cast(month('5/15/2009') as varchar(2)) + 
        '/1/' + 
        cast(year('5/15/2009') as varchar(4)))

Upvotes: 2

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