Piotr Sobczyk
Piotr Sobczyk

Reputation: 6583

Hibernate @OrderBy for nested properties

I need to use @OrderBy (JPA, Hibernate as provider) to sort collection for nested property:

@OneToMany(mappedBy = "paramSpec", cascade = CascadeType.ALL)
@OrderBy("release.ordinal")
private List<PkdbParameter> pkdbParams;

In PkdbParameter.java:

...
@ManyToOne
@JoinColumn(name = "release_id")
private Release release;
...

In Release.java:

...
private int ordinal;
...

(all of these fields have simple getters and setters provided)

Unfortunately I'm getting error:

Caused by: org.hibernate.AnnotationException: property from @OrderBy clause not found: some.package.PkdbParameter.release.ordinal

What's wrong with this code? If it's impossible to use nested properties notation is there any other way to order for ordinal property?

Upvotes: 13

Views: 11510

Answers (3)

Vlad Mihalcea
Vlad Mihalcea

Reputation: 153730

You can use the Hibernate @SortComparator annotation:

Like this:

@OneToMany(mappedBy = "paramSpec", cascade = CascadeType.ALL)
@SortComparator(ReleaseComparator.class)
private List<PkdbParameter> pkdbParams;

Where CameraNameComparator is:

public class ReleaseComparator implements Comparator<PkdbParameter> {
    @Override
    public int compare(PkdbParameter o1, PkdbParameter o2) {
        return o1.getRelease().getOrdinal().compareTo( o2.getRelease().getOrdinal() );
    }
}

Upvotes: 11

Tires
Tires

Reputation: 1602

You can split the order statements and place it on non collection properties:

@OneToMany(mappedBy = "paramSpec", cascade = CascadeType.ALL)
@OrderBy("release")
private List<PkdbParameter> pkdbParams;

and

@ManyToOne
@JoinColumn(name = "release_id")
@OrderBy("ordinal")
private Release release;

As a side effect, you have fixed sort order for PkdbParameter.

Upvotes: 0

anergy
anergy

Reputation: 1384

@OrderBy works only with direct properties or embedded attributes. From Java EE 6 docs

The dot (".") notation is used to refer to an attribute within an embedded attribute

So if the Release is an embedded attribute, this could work. Otherwise you could use named query as suggested here

Upvotes: 4

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