Reputation: 421
I have got a Problem, I am developing an Application which should be able to do some mathematic calculations. These calculations have to be exact (or rather not obviously wrong)
But this simple Code
double a = 3.048d;
double b = 1000d;
double c = a / b;
gives me a wrong result c is not 0.003048 as expected instead it is 0.0030480000000000004 which is obviously wrong.
double d = 3.048 / 1000;
this second code-snipet gives the correct result.
I am aware that all floatingpoint arithmetic is not exact when calculating with computers but I don't know how to solve this problem.
thanks in advance!
Ludwig
Developing for:
- Android 2.2
Testdevice:
- HTC Desire
Upvotes: 0
Views: 395
Reputation: 3848
Use a BigDecimal for precise floating point calculations. Setting the scale allows you to specify precisely how far out you want to go for output.
import java.math.BigDecimal;
class Test{
public static void main(String[] args){
BigDecimal a = new BigDecimal("3.048");
BigDecimal b = new BigDecimal(1000);
BigDecimal c = a.divide(b).setScale(6);
System.out.println(c); //0.003048
}
}
Upvotes: 1
Reputation: 2598
This is a consequence of the IEEE 754 floating point representation, not an error. To deal with it, round your result to an appropriate precision.
Upvotes: 1
Reputation: 11113
What you need to use for exact percision is the BigDecimal object:
BigDecimal a = new BigDecimal("3.048");
BigDecimal b = new BigDecimal(1000);
BigDecimal c = a.divide(b);
System.out.println(c); //0.003048
Upvotes: 5
Reputation: 26333
Use BigDecimal for such precise allocations.
Btw the result for d is obviously right, because double has a machine encoding which cannot store the result, which you perceive as correct.
Upvotes: 0