Reputation: 51
How can we sftp a file from source host to a destinition server in python by invoking unix shell commands in python script using os.system...Please help
I have tried the following code
dstfilename="hi.txt"
host="abc.com"
user="sa"
os.system("echo cd /tmp >sample.txt)
os.system("echo put %(dstfilename)s" %locals()) // line 2
os.system("echo bye >>sample.txt")
os.system("sftp -B /var/tmp/sample.txt %(user)s@%(host)s)
How to append this result of line to sample.txt?
os.system("echo put %(dstfilename)s %locals()) >>sample.txt" // Seems this is syntatically not correct.
cat>sample.txt //should look like this
cd /tmp
put /var/tmp/hi.txt
bye
Any help?
Thanks you
Upvotes: 4
Views: 6821
Reputation: 5593
If you want a non-zero return code if any of the sftp commands fail, you should write the commands to a file, then run an sftp batch on them. In this fashion, you can then retrieve the return code to check if the sftp commands had any failure.
Here's a quick example:
import subprocess
host="abc.com"
user="sa"
user_host="%s@%s" % (user, host)
execute_sftp_commands(['put hi.txt', 'put myfile.txt'])
def execute_sftp_commands(sftp_command_list):
with open('batch.txt', 'w') as sftp_file:
for sftp_command in sftp_command_list:
sftp_file.write("%s\n" % sftp_command)
sftp_file.write('quit\n')
sftp_process = subprocess.Popen(['sftp', '-b', 'batch.txt', user_host], shell=False)
sftp_process.communicate()
if sftp_process.returncode != 0:
print("sftp failed on one or more commands: {0}".format(sftp_command_list))
Quick disclaimer: I did not run this in a shell so a typo might be present. If so, send me a comment and I will correct.
Upvotes: 0
Reputation: 91149
You should pipe your commands into sftp
. Try something like this:
import os
import subprocess
dstfilename="/var/tmp/hi.txt"
samplefilename="/var/tmp/sample.txt"
target="sa@abc.com"
sp = subprocess.Popen(['sftp', target], shell=False, stdin=subprocess.PIPE)
sp.stdin.write("cd /tmp\n")
sp.stdin.write("put %s\n" % dstfilename)
sp.stdin.write("bye\n")
[ do other stuff ]
sp.stdin.write("put %s\n" % otherfilename)
[ and finally ]
sp.stdin.write("bye\n")
sp.stdin.close()
But, in order to answer your question:
os.system("echo put %(dstfilename)s %locals()) >>sample.txt" // Seems this is syntatically not correct.
Of course it isn't. You want to pass a stringto os.system. So it has to look like
os.system(<string expression>)
with a )
at the end.
The string expression consists of a string literal with an applied %
formatting:
"string literal" % locals()
And the string literal contains the redirection for the shell:
"echo put %(dstfilename)s >>sample.txt"
And together:
os.system("echo put %(dstfilename)s >>sample.txt" % locals())
. But as said, this is the worst solution I can imagine - better write directly to a temp file or even better pipe directly into the sub process.
Upvotes: 7
Reputation: 3209
Well, I think the literal solution to your question would look something like this:
import os
dstfilename="/var/tmp/hi.txt"
samplefilename="/var/tmp/sample.txt"
host="abc.com"
user="sa"
with open(samplefilename, "w") as fd:
fd.write("cd /tmp\n")
fd.write("put %s\n" % dstfilename)
fd.write("bye\n")
os.system("sftp -B %s %s@%s" % (samplefilename, user, host))
As @larsks says, use a proper filehandler to make the tmp file for you, and my personal preference is to not to do string formatting using locals()
.
However depending on the use case, I don't think this is a particularly suitable approach - how does the password the sftp site get entered for example?
I think you'd get a more robust solution if you took a look at the SFTPClient in Paramiko, or failing that, you might need something like pexpect to help with ongoing automation.
Upvotes: 0