Reputation: 501
So I have a function like this:
function music(song) {
var audio = new Audio("audio/" + song + ".ogg");
audio.play();
}
And the problem I'm having is that audio.play() works perfectly, but if I try audio.pause() later (after defining the same variable), it doesn't work. However, if I do this:
function music() {
var audio = document.getElementById("songname");
audio.play();
}
Then I can define the variable and later use audio.pause() to pause the track. The problem is that I want to do this within javascript because I have a lot of tracks and I don't want to create audio elements for each one.
Why doesn't the first piece of code allow me to pause the audio later? Is there any way I can let it pause the audio later? If not, are there any alternatives that involve playing the audio from javascript by passing a parameter which is the song title? I don't want to have to include the src in the html.
I suspect that jQuery might have an easy solution for this but form what I've researched I couldn't find anything.
Upvotes: 0
Views: 2431
Reputation: 133
You can create the audio variable before defining the function.
var audio = new Audio();
function playMusic(song) {
audio.src = "audio/" + song + ".ogg";
audio.play();
}
function pauseMusic() {
audio.pause();
}
Upvotes: 0
Reputation: 78971
I just tested a snippet and it works as such
function music(song) {
var audio = new Audio("audio/" + song + ".ogg");
audio.play();
setTimeout(function() { audio.pause(); }, 5000);
}
Upvotes: 0
Reputation: 60413
audio
only exists inside the function. if you need access to it outside the function then return the instance of the Audio
object you are creating:
function getAudio(song, play) {
var audio = new Audio("audio/" + song + ".ogg");
if(play) {
audio.play();
}
return audio;
}
var theTrack = getAudio('my_song', true);
theTrack.pause(); // pause the song
theTrack.play(); // play the song
The second example refers to what i assume is an audio element which in turn exposes the functionality of the Audio
object. The reason the second function works anywhere is because the DOM element is always present in the DOM and you are referencing that to get at the underlying Audio API, as opposed to a using the Audio object/API directly.
Upvotes: 1