Reputation: 2809
How can I find all indexes of a pattern in a string using c#?
For example I want to find all ##
pattern indexes in a string like this 45##78$$#56$$JK01UU
Upvotes: 5
Views: 15402
Reputation: 10341
Edited the code to make it a cleaner function.
public IEnumerable<int> FindAllIndexes(string str, string pattern)
{
int prevIndex = -pattern.Length; // so we start at index 0
int index;
while((index = str.IndexOf(pattern, prevIndex + pattern.Length)) != -1)
{
prevIndex = index;
yield return index;
}
}
string str = "45##78$$#56$$JK01UU";
string pattern = "##";
var indexes = FindAllIndexes(str, pattern);
Upvotes: 3
Reputation: 4361
string pattern = "##";
string sentence = "45##78$$#56$$J##K01UU";
IList<int> indeces = new List<int>();
foreach (Match match in Regex.Matches(sentence, pattern))
{
indeces.Add(match.Index);
}
indeces will have 2, 14
Upvotes: 9
Reputation: 20046
Tested. Worked. But somewhat dumb.
string foo = "45##78$$#56$$JK01UU";
char[] fooChar = foo.ToCharArray();
int i = 0;
bool register = false;
foreach (char fc in fooChar)
{
if (fc == '#' && register == true)
{
MessageBox.Show("Index: " + (i-1));
}
else if (fc == '#')
{
register = true;
}
else
{
register = false;
}
i++;
}
Upvotes: 0
Reputation: 102753
You can get all the indices of a pattern in a string by using a regex search like this.
string input = "45##78$$#56$$JK01UU", pattern = Regex.Escape("##");
Regex rx = new Regex(pattern);
var indices = new List<int>();
var matches = rx.Matches(s);
for (int i=0 ; i<matches.Length ; i++)
{
indices.Add(matches[i].Index);
}
Upvotes: 2
Reputation: 15618
Another one that tries to be efficient:
public IEnumerable<int> FindPatternIndexes(string input, string search)
{
var sb = new StringBuilder(input);
for (var i = 0; search.Length <= sb.Length; i++)
{
if (sb.ToString().StartsWith(search)) yield return i;
sb.Remove(0,1);
}
}
Upvotes: 0