Reputation:
Suppose I have a class with a factory method
class A {
public:
static A* newA()
{
// Some code, logging, ...
return new A();
}
}
Is it possible to prevent the instantiation of an object of this class with a new
, so that factory method is the only method to create an instance of the object?
Upvotes: 5
Views: 2767
Reputation: 272517
Sure; just make the constructor private (protected if this is a base class):
class A {
public:
static A* newA()
{
// Some code, logging, ...
return new A();
}
private:
A() {} // Default constructor
};
You should make the copy constructor private/protected as well, if required.
And as always, you should strongly consider returning a smart pointer rather than a raw pointer, in order to simplify memory management issues.
Upvotes: 8
Reputation: 16197
You may also want to make the copy constructor private as well or with new C++11 syntax you can explicitly tell the compiler to not copy it and make the default constructor private with something like this:
struct NonCopyable {
NonCopyable & operator=(const NonCopyable&) = delete;
NonCopyable(const NonCopyable&) = delete;
NonCopyable() = default;
};
class A : NonCopyable {
public:
static std::shared_ptr<A> newA()
{
// Some code, logging, ...
return std::make_shared<A>();
}
private:
A() {} // Default constructor
};
The C++03 way was usually something like this:
class A {
public:
static A* newA()
{
// Some code, logging, ...
return new A();
}
private:
A() {} // no outsider default constructor
A(const A& rhs); // no copy
A& operator=(const A& rhs); // no assignment
};
int main()
{
A x; // C2248
A y(x); // C2248
x = y; // C2248
A* p = A::newA(); // OK
std::cin.get();
return 0;
}
Upvotes: 3